Help please!!!! Picture is attached

Question

Help please!!!!  Picture is attached

whpalmer4 · Answer

no picture...

marcelie · Answer

attachment

marcelie · Answer

number 9 i dont understand it

marcelie · Answer

what does it mean : whether the curve is the graph of a function of x. 
Bc i know the domain is from left to right ..

directrix · Answer

Use the vertical line test to determine if the graph is that of a function.
Attached.

marcelie · Answer

so wouldnt that be a v. line test bc theres two dots in same line

mathmale · Answer

Actually, "domain" includes more than "left to right."  The domain of a function lists (or gives a rule for) input (or x-) values that are permitted.  For example, you cannot find the square root of a negative number (unless you're willing to consider imaginay results).  So the domain of the sqrt of x is "All real numbers 0 or greater."

mathmale · Answer

Yes, "vertical line test" applies here.   Draw a vert line thru several different x values and count how many times the line intercepts the graph.  More than once:  Then your graph does not repr. a function.

marcelie · Answer

oh how come my answer sheet said its a fucntion o.o

mathmale · Answer

Think about what I said earlier, and then you tell me.

marcelie · Answer

i dont get it D:

directrix · Answer

Where do you see this:

>>  bc theres two dots in same line 

That is, two points on the same vertical line.

I think I am looking at a "hollowed point" at (-2, -2).

Look and see if you agree. @marcelie

marcelie · Answer

yes i see it .. and thres a closed circle below it

directrix · Answer

So, (-2,-2) and (-2,-1) are not two points on the same vertical line.

(-2, -2) is not a point on the graph.

I see an open circle there.

marcelie · Answer

yes. so does that make a fucntion?

directrix · Answer

To clarify, do you see this (attached) as open?

On the graph, if the x of -2 is paired with the y of -2 and also with the y of -1, then the graph is not that of a function.

A given x of the function can be paired with exactly one y.

That appears to be the case here if there is an open circle on (-2, -2).

That established, it is time for the domain and range.

marcelie · Answer

i saw it, so therefore it is fucntion ?

directrix · Answer

>>>so therefore it is fucntion ?

Yes, it is for reasons posted earlier in the thread.

@marcelie