Question

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Answer 1

the derivative of x is 1

Answer 2

the derivative of 2 is 0

Answer 3

and for the derivative of \(xy\) you need the product rule \[xy'+y\]

Answer 4

so you get \[xy'+y=1\] solve for \(y'\)

Answer 5

if that is not clear, imagine \(y=f(x)\)
you take the derivative of \(xf(x)\) by the product rule and get \(xf'(x)+f(x)\)

Answer 6

yes \(\frac{1-y}{x}\) from algebra

Answer 7

In this case, if you were desperate, you could first solve for y. Not really the point of the exercise, though.

Answer 8

Thank you!!!