for the function f, construct and simplify the difference quiotent f(x+h)-f(x) ------ h f(x)=x/4-x
omgg im learning this... what college do you go too?
\[\frac{ f(x+h)-f(x) }{ h }\]
I assume that is \[f(x)=\frac{x}{4-x}\]
valencia, and yes that is
ok, so replace \(x\) with \(x+h\) in \(f(x)\), what do you get?
\[\frac{ x+h }{ 4-x+h }\]
not quite. \[4-(x+h)=\]
\[4(-x-h)\]
\[4-(x+h)=4-x-h\]right?
yes!
ok, so \[f(x+h)=\frac{x+h}{4-x-h}\] \[f(x)=\frac{x}{4-x}\] \[\frac{f(x+h)-f(x)}{h}=\]
some tedious but straightforward algebra to do...
so i need to get rid of the "h" by multiplying ?
no, you need to make a common denominator so you can add the two fractions, then divide the mess by h
Valencia? Ooo nice :) I'm over at UCF.
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