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Mathematics 6 Online
OpenStudy (unique_am_i):

Will medal for ASAP help in Geom!

OpenStudy (unique_am_i):

Find the value of X,Y and Z

OpenStudy (unique_am_i):

DEFG. DH=x+1 HF=3y GH=3x-4 HE=5y+1. Find the value of Y and X

OpenStudy (vijeya3):

Since the first figure is a parallelogram... x=33(Since alternate interior angles are equal) By angle sum property of a triangle, 33+109+y=180 y=180-142 y=38 z=109(Opposite angles are equal in a parallelogram)

OpenStudy (vijeya3):

Is the second one a parallelogram too?

OpenStudy (unique_am_i):

Yes it is. Thanks so much for helping me with the first! I couldn't figure it out haha

OpenStudy (vijeya3):

Then in the second one,we know that the diagonals of a parallelogram bisect each other..... so,DH=HF and GH=HE x+1=3y x=3y-1 (equation number1) then since GH=HE..so, 3x-4=5y+1 Placing the value of x from equation 1 in this one,we get.. 3(3y-1)=5y+1 9y-3=5y+1 9y-5y=1_4 4y=4 y=1 Placing this in equation 1 you will get.... x=3y-1 =3(1)-1 3-1 =2 x=2 Therefore,x=2 and y=1 If this is helpful,fan and medal me..:)

OpenStudy (unique_am_i):

Thank you so so much!

OpenStudy (unique_am_i):

@Vijeya3 could you help me with one more? ON=8x-8 LM=7x+4 NM=x-5 OL=3y-6. Find the value of X and Y. (Its a parallelogram)

OpenStudy (vijeya3):

sure :)

OpenStudy (vijeya3):

Since it is a parallelogram,ON=LM and MN=OL(Opposite sides of a parallelogram are equal) therefore .. 8x-8=7x+4 8x-7x=4+8 x=12 Now for MN=OL, it'd be.. x-5=3y-6 taking the value of x from above... 12-5=3y-6 7=3y-6 3y=13 y=13/3 y=4.33(approx) so u have.. X=12 and y=4.33

OpenStudy (unique_am_i):

@Vijeya3 Thank you so so much! I really appreciate it!

OpenStudy (vijeya3):

never mind:)tag me whenever you need help..btw which standard questions are these?

OpenStudy (unique_am_i):

geometry b. Its for unit 2 lesson 3 in connections education

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