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Chemistry 17 Online
OpenStudy (priyar):

can anyone explain "work done in an adiabatic expansion"?

OpenStudy (priyar):

@Photon336 @sweetburger @freckles @zepdrix @dan815

OpenStudy (priyar):

i have one doubt..why does the temperature do down?

OpenStudy (priyar):

*go

OpenStudy (priyar):

temperature must increase for the gas to expand.. right?

OpenStudy (photon336):

The heat re-mains constant in this process

OpenStudy (priyar):

ok...so?

OpenStudy (priyar):

do u mean to say temp. won't change..?

OpenStudy (photon336):

Are you familiar with internal energy?

OpenStudy (priyar):

yes

OpenStudy (priyar):

@Photon336 ?

OpenStudy (photon336):

@aaronq @sweetburger

OpenStudy (priyar):

but this is not isothermal process...this is adiabatic process where change in heat is zero..

OpenStudy (priyar):

@ShadowLegendX @Luigi0210

OpenStudy (priyar):

@mayankdevnani @Astrophysics

OpenStudy (mayankdevnani):

https://www.youtube.com/watch?v=w04Kd3wIrMI

OpenStudy (priyar):

thanks i saw..the videos..but it doesn't say anything abt "sign"...i wanna know why temp. decreases in an adiabatic "expansion". coz temperature must increase for the gas to expand.. right? @mayankdevnani

OpenStudy (priyar):

@ParthKohli @samigupta8

OpenStudy (samigupta8):

Bcz ∆U=∆W in adiabatic...hence work done is given as -PextdV ....n volume change wud be positive so work is negative....so change in internal energy is -ve

OpenStudy (priyar):

ya..but i wanna know the physical meaning..

OpenStudy (priyar):

not on formula basis..

OpenStudy (frostbite):

Okay so lets first establish: Adiabatic means no transfer of energy through the heating process: \(q_{ad}=0\) Now lets take a look at what happens to an ideal gas it expands from volume \(V_i\) to \(V_f\): The gas is performing work on the surroundings \(w_{ad}<0\) This means the change in internal energy is falling, \(\Delta U<0 \), because the lose of energy is done adiabatic \(\Delta U=w_{ad}\) The internal energy of an ideal gas depends only on the temperature and not the volume. This means the temperature is falling from \(T_i\) to \(T_f\) when the internal energy is falling. For this reason we can write the internal energy as: \[\Large w_{ad}=\Delta U=C_V \Delta T\] The fact the temperature is dropping in an adiabatic expansion can also be understood though statistical mechanics (what I consider the physical meaning if people ask): Adiabatic literally mean the population of the individual energy states is not altered, but rather the states are moving closer towards each other. In order to forefil this, the temperature within the Boltzmann distribution needs to decrease. (as explained in more detail in my tutorial in thermodynamics and the internal energy). Within in the macroscopic framework of thermodynamics not all concepts can be explains perfectly. I admit that.

OpenStudy (frostbite):

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