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Mathematics 7 Online
OpenStudy (anonymous):

what is the asymptote of 4/x-5

OpenStudy (anonymous):

@Astrophysics

OpenStudy (anonymous):

@chainedecho

OpenStudy (color):

@adi3

OpenStudy (mathwizzard3):

@milk333

OpenStudy (anonymous):

@color he is offline

OpenStudy (mathwizzard3):

@Awolflover1 @chalkskull

OpenStudy (anonymous):

@iGreen @igigighjkl

OpenStudy (igigighjkl):

Hu?

OpenStudy (igreen):

Horizontal or vertical asympotote?

OpenStudy (igreen):

asymptote*

OpenStudy (anonymous):

both

OpenStudy (igreen):

If vertical, solve the equation in the denominator. x - 5 = 0 Can you solve that for 'x'?

OpenStudy (igigighjkl):

I in 6th grade...

OpenStudy (igigighjkl):

me don't no.

OpenStudy (anonymous):

x = 5

OpenStudy (igreen):

Correct, that's our vertical asymptote.

OpenStudy (anonymous):

ok

OpenStudy (igreen):

To find horizontal asymptotes: If the degree (the largest exponent) of the denominator is bigger than the degree of the numerator, the horizontal asymptote is the x-axis (y = 0). If the degree of the numerator is bigger than the denominator, there is no horizontal asymptote. If the degrees of the numerator and denominator are the same, the horizontal asymptote equals the leading coefficient (the coefficient of the largest exponent) of the numerator divided by the leading coefficient of the denominator

OpenStudy (igreen):

What's the degree of the numerator?

OpenStudy (anonymous):

how do you check that

OpenStudy (igreen):

Degree is the highest exponent. 4 is the only term in the numerator, do you know what the degree is?

OpenStudy (anonymous):

|dw:1455204026573:dw|

OpenStudy (igreen):

The degree of every regular number is 1. Because \(\sf 4^1 = 4\)

OpenStudy (igreen):

So the degree of the numerator is 1. How about the denominator?

OpenStudy (anonymous):

but we got taught like this. we need to make both zero

OpenStudy (igreen):

Oh wait..the degree is actually 0..nevermind.

OpenStudy (igreen):

Since there is no variable in the numerator it's 0..for the denominator, we have an 'x', so what's the degree there?

OpenStudy (anonymous):

1

OpenStudy (igreen):

Correct..so the degree in the numerator is less than the degree in the denominator..so look back at the statements I posted earlier and tell me what the horizontal asymptote will be.

OpenStudy (anonymous):

horizontal is 5 vertical is 0

OpenStudy (anonymous):

but isnt 4^0 1 too

OpenStudy (igreen):

That has nothing to do with this.

OpenStudy (igreen):

We said the degree in the numerator is less than the degree in the denominator..so which statement matches that? If the degree (the largest exponent) of the denominator is bigger than the degree of the numerator, the horizontal asymptote is the x-axis (y = 0). If the degree of the numerator is bigger than the denominator, there is no horizontal asymptote. If the degrees of the numerator and denominator are the same, the horizontal asymptote equals the leading coefficient (the coefficient of the largest exponent) of the numerator divided by the leading coefficient of the denominator

OpenStudy (anonymous):

a

OpenStudy (igreen):

Yep! So the horizontal asymptote is the x-axis or y = 0

OpenStudy (igreen):

VA is x = 5 HA is y = 0

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