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Find the 10th partial sum of the summation of \[\sum_{i-1}^{\infty}-5i+2\]
I= -5(1) + 2 = -5+2= -3 I= -5(2) + 2= -10+2= -8 I = -5(3)+2 = -15+2= -13 = -5(4)+2= -20+2= -18 = -5(5)+2= -25+2= -23 = -5(6)+2=-30+2= = -5(7)+2= -35+2= = -5(8)+2= -40+2= = -5(9)+2= -45+2= = -5(10)+2= -50+2= Solve each equation then add all 10 totals together to get ur 10th partial sum for the summation.(I completed the first 5) Don't forget u should have a negative answer😁 your answer should be in this form ( the original equation) -3-8-13-18-23-28-33-38-43-48= -255 Answer: ∑i−1∞(-5i+2) = -255
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