Question

simple question

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{A does a piece of work in \(12\) days and }\hspace{.33em}\\~\\
& \normalsize \text{B does the same work in \(9\) days . }\hspace{.33em}\\~\\
& \normalsize \text{If they work on alternate days starting from A. }\hspace{.33em}\\~\\
& \normalsize \text{In how many days will the work be completed ? }\hspace{.33em}\\~\\
\end{align}}\)

Answer 2

Have you considered how you will represent your unknown quantities, or how those quantities are related through equations? That's the place to startl.

Answer 3

I feel like you should make these into decimals or fractions... so 1/12 for a and 1/9 for another... and then you have \[1/12+1/9\] and then that \[+1/12\] then that \[+1/9\]

Answer 4

0.08333333333333333333333333333333 is 1/12 and 0.11111111111111111111111111111111 is 1/9

Answer 5

sorryi was wrong

Answer 6

then find out how many times you have to do that to get to the whole number (1)

Answer 7

i didnt understand

Answer 8

so (a) gets 1/12 of the work done in one day because it takes them 12 days to get one piece of work done.
do you understand that?

Answer 9

yes

Answer 10

and (b) gets 1/9 of work done each day because he gets one piece of work done every 9 days.
understand that?

Answer 11

yes

Answer 12

so you have to cross multiply to get a common denominator

Answer 13

so then you just have to add (9+12) which is two times +9 (three) +12 (four) till you get to 108.

Answer 14

is that my answer

Answer 15

does that make sense?

Answer 16

is 21/108 = answer

Answer 17

no. do the work. im not doing it for you

Answer 18

i even told you how to do it. "so then you just have to add (9+12) which is two times +9 (three) +12 (four) till you get to 108-2 minutes ago"

Answer 19

0.19 ?

Answer 20

i did my work

Answer 21

your trying to get 108 by going back and fourth adding 9+12

Answer 22

there is no decimal.

Answer 23

why dont you use the "draw" and do the work and then post it