Question

In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?

Quadratic formula: x =

Answer 1

\[x = 5 \pm \sqrt{31}\]

Answer 2

If you need further explanation I can do?

Answer 3

you should do that
direct answers are not allowed in Open Study

Answer 4

Ok let me explain then

Answer 5

thanks for the opinion lol

Answer 6

\[x^2 - 10x - 6 = 0 \\ x^2 - 10x + 25 - 25 - 6 = 0\]
I added 25 to make it in this form \[(a + b)^2\] and to make no effect we have to subtract 25 too.
so
\[(x - 5)^2 - 31 = 0 \\ (x - 5)^2 - (\sqrt[2]{31})^2 = 0\\ (x - 5 + \sqrt{31})(x - 5 - \sqrt{31}) = 0 \\\]
so
\[x = 5 \pm \sqrt{31}\]

Answer 7

i used \[(a^2 - b^2) = (a - b)(a+b)\]