Question

what is x+3y=5 in polar form

Answer 1

i think it is \[r \cos \theta-3rsin \theta=5\]

Answer 2

ahemm hint \({\color{brown}{ x}}+3{\color{blue}{ y}}=5\qquad \qquad
\begin{cases}
{\color{brown}{ x}}=rcos(\theta)\\
{\color{blue}{ y}}=rsin(\theta)
\end{cases}\)

replace, and solve for "r"
since polar equations are written as an "r" function in \(\theta\) terms

Answer 3

yeap one sec

Answer 4

\({\color{brown}{ x}}+3{\color{blue}{ y}}=5\qquad \qquad
\begin{cases}
{\color{brown}{ x}}=rcos(\theta)\\
{\color{blue}{ y}}=rsin(\theta)
\end{cases}
\\ \quad \\ \quad \\
rcos(\theta)+3rsin(\theta)=5\implies r[cos(\theta)+3sin(\theta)]=5
\\ \quad \\
r=\cfrac{5}{[cos(\theta)+3sin(\theta)]}\)

Answer 5

hmm rats, missing an "r" there on the 2nd line

anyway \(rcos(\theta)+3rsin(\theta)=5\implies r[cos(\theta)+3rsin(\theta)]=5
\\ \quad \\
r=\cfrac{5}{[cos(\theta)+3sin(\theta)]}\)

Answer 6

so how would i do this problem \[y=3x^2 +1\] and change it into polar

Answer 7

@jdoe0001

Answer 8

one sec

Answer 9

ok

Answer 10

try posting it anew.... while I see what I can find
someone else may know it, and I'll check as well

Answer 11

okay