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Mathematics 14 Online
OpenStudy (anonymous):

In the figure below, mJSR = 53° and mSLN = 78°. Note: picture not drawn to scale What is mLNS? A. 49° B. 74° C. 24° D. 131°

OpenStudy (anonymous):

OpenStudy (anonymous):

here is the picture

OpenStudy (anonymous):

thease are really hard for me

OpenStudy (anonymous):

i got A

OpenStudy (anonymous):

is that correct

OpenStudy (jtug6):

It's been awhile since I took geometry but that appears to be correct. How did you conclude that it was 49 degrees though?

OpenStudy (jtug6):

I'd wait for someone else to help you work through it. Perhaps @mathmale?

OpenStudy (jtug6):

Or @Astrophysics

OpenStudy (jtug6):

How would you go about first finding JSL given that angle JSR is 53 degrees? (There's probably an easier way about solving with the use of a postulate but I don't remember)

OpenStudy (jtug6):

angle JSL I should add

OpenStudy (mathstudent55):

|dw:1455254580332:dw|

OpenStudy (mathstudent55):

|dw:1455254753587:dw|

OpenStudy (mathstudent55):

x + y + 78 = 180 Since m<JSR = 53, and angles JSR and LSN are vertical angles, then m<LSN = 53. x + 53 + 78 = 180 x + 131 = 180 x = 49 m<LNS = 49

OpenStudy (jtug6):

Aren't we supposed to guide them through it?

OpenStudy (anonymous):

terrible...

OpenStudy (mathstudent55):

He already got the answer. He said above it was A. That answer is correct.

OpenStudy (anonymous):

i am sorry to say this but i am not a boy I am a girl

OpenStudy (anonymous):

lol

OpenStudy (mathstudent55):

Don't be sorry. Sorry to refer to you as "he". I'll rewrite it then. She already got the answer. She said above it was A. That answer is correct.

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