Mathematics
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OpenStudy (anonymous):
evaluate the integral of sec^2(x)/sqrt(1+tan(x) Show work?
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OpenStudy (xapproachesinfinity):
@Alexkwkwl still need help
OpenStudy (anonymous):
Yes please
OpenStudy (xapproachesinfinity):
So what are your thoughts
OpenStudy (xapproachesinfinity):
let's just make sure we have the right integral \[\int \frac{\sec^2x}{\sqrt{1+\tan x}}dx\]
OpenStudy (xapproachesinfinity):
is this what you have
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OpenStudy (anonymous):
Yes
OpenStudy (xapproachesinfinity):
how about a sub in there?
OpenStudy (anonymous):
A sub?
OpenStudy (xapproachesinfinity):
substitution
OpenStudy (anonymous):
No
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OpenStudy (xapproachesinfinity):
why not?
OpenStudy (anonymous):
Oh you mean like 1/cos
OpenStudy (xapproachesinfinity):
this sub works good \[u=1+\tan x\]
OpenStudy (xapproachesinfinity):
\[du=\sec^2x dx \]
OpenStudy (xapproachesinfinity):
you can see it now?
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OpenStudy (anonymous):
Wait And then what do you do
OpenStudy (xapproachesinfinity):
you substitute \(\sec^2x dx\) for \(du\)
OpenStudy (anonymous):
Yes i know that
OpenStudy (xapproachesinfinity):
and \(1+\tan x \) for u
OpenStudy (xapproachesinfinity):
then work the integral with u
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OpenStudy (xapproachesinfinity):
so?
OpenStudy (xapproachesinfinity):
this is what you get \[\int \frac{du}{ \sqrt{u}}\]
OpenStudy (xapproachesinfinity):
you should be able to integrate this one easily
OpenStudy (anonymous):
2?
OpenStudy (xapproachesinfinity):
what you mean by two?
remember indefinite integral gives a family of functions
meaning an anti-derivative with a constant C
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OpenStudy (xapproachesinfinity):
you should not get a numerical value
OpenStudy (anonymous):
2 times sqrtu +c
OpenStudy (xapproachesinfinity):
yes! now revert back to 1+tanx
OpenStudy (xapproachesinfinity):
remember that we set u=1+tanx
OpenStudy (anonymous):
2(1+Tanx) +C
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OpenStudy (xapproachesinfinity):
no
OpenStudy (xapproachesinfinity):
you forgot something
OpenStudy (anonymous):
Oh the sqrt lol duh
OpenStudy (xapproachesinfinity):
yeah
OpenStudy (anonymous):
That's it??
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OpenStudy (xapproachesinfinity):
yep
OpenStudy (anonymous):
Omg yay thank you so much
OpenStudy (xapproachesinfinity):
yeah you doing great :)
you are welcome