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Mathematics 14 Online
OpenStudy (anonymous):

1 Math eazy

OpenStudy (anonymous):

@jabez177

OpenStudy (anonymous):

@pooja195

OpenStudy (michele_laino):

hint: |dw:1455304363995:dw| both triangles ABC and ABD are isosceles triangles. Now I ask what is the x-coordinate of the point P

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

3 0r 4?

OpenStudy (michele_laino):

hint: we have isosceles triangles, if the point P is the midpoint of the segment AB please keep in mind that point P is the orthogonal projection of both points C and D

OpenStudy (anonymous):

idk what mm im not crazy good at math can u explain

OpenStudy (michele_laino):

let's consider this isosceles triangle: |dw:1455304839899:dw| P is the midpoint of the segment AB, so we can write: AP=PB

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

i gtg soon i also have ti finish this test like 15 minetes

OpenStudy (michele_laino):

now, sarting from the coordinates of the points A and B, of the diagram you provided, we can write the x-coordinate of point P, like below: \[\Large {x_P} = \frac{{{x_A} + {x_B}}}{2} = \frac{{ - 2 + 4}}{2} = ...?\]

OpenStudy (michele_laino):

oops..starting*

OpenStudy (anonymous):

?

OpenStudy (michele_laino):

what is \(-2+4=...?\)

OpenStudy (anonymous):

2 or 6

OpenStudy (michele_laino):

we have this: \(-2+4=4-2=...?\)

OpenStudy (michele_laino):

what is \(4-2=...?\)

OpenStudy (anonymous):

2

OpenStudy (michele_laino):

ok! And what is \(2/2=...?\)

OpenStudy (anonymous):

idk

OpenStudy (michele_laino):

we have \(2/2=1\) since \(2 \times 1=2\), am I right?

OpenStudy (anonymous):

yes

OpenStudy (michele_laino):

ok! So, the x-coordinate of point P is: \[\Large {x_P} = \frac{{{x_A} + {x_B}}}{2} = \frac{{ - 2 + 4}}{2} = 1\]

OpenStudy (anonymous):

yes

OpenStudy (michele_laino):

now, the x.coordinate of the third point has to be \(1\), since point P is the orthogonal projection of the requested third point. So, what are the right options?

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