Question

Need help in graphing!

Answer 1

Im graphing it

Answer 2

I need to fint the area

Answer 3

@mathmath333 @math&ing001 @RhondaSommer @AloneS @Electric_Blue can you guys help me?

Answer 4

its easy just divide the diagram in 3 triangles and i rectangle

Answer 5

ok.

Answer 6

ok

Answer 7

i hope u know how to find the area of triangle and rectangle

Answer 8

yess?.... lol

Answer 9

triangle- (b*h)/2 rectangle b*h

Answer 10

thanks :)

Answer 11

no problem :)

Answer 12

so what would be the measeurments? Im confused :(

Answer 13

you should put in the missing numbers. for example point E is at x=5 and y=3

Answer 14

so it would be for triangle AFE
B= 5,3
H=5,6??

Answer 15

I don't follow

Answer 16

im confused, i don't know what im supposed to put in for Base and Height

Answer 17

You count lines or boxes. But it looks like two lines is "one step"
For example, along the x-axis, it takes 4 lines to get to the label 2
so two lines is 1 step
The easiest way to keep it clear is label the (x,y) of each point
for example, any idea what the (x,y) are for point A at the very top?

Answer 18

no

Answer 19

put your finger at the (0,0) where the x and y axis cross
move sideways along the x-axis until you are directly beneath point A
what label are you at (on the x-axis) ?

Answer 20

5

Answer 21

that is the x value of A
for the y, you move straight up until you are at point A. You will go up to 6

Answer 22

so A is at (5,6)

can you say the (x,y) for point E ?

Answer 23

E = (5,3 )

Answer 24

for the triangle AEF, the height is from E to F (straight up)
E is at y=3 and A is at height 6
what is the difference between 6 and 3?

Answer 25

does that make sense?

Answer 26

yes

Answer 27

the curved lines represent 1 :)

Answer 28

for the triangle AEF, the height is from E to A (straight up)
E is at y=3 and A is at height 6
what is the difference between 6 and 3?

Answer 29

all you have to do is cound the distance from each point except ot the \ curved lines :)

Answer 30

count*

Answer 31

make sense :)

Answer 32

brb

Answer 33

we are aware @mathmath333

Answer 34

just to draw straight lines :)

Answer 35

you could also use the distance formula :)
\[\sqrt{(x^2-x^1)+(y^2-y^1)}\]

Answer 36

just for future refrence :)

Answer 37

yea but in this case the length can be seen just from the diagram, no neccesarry use of the formula

Answer 38

ok.

Answer 39

i know. "just for future refrence"

Answer 40

did u get all the lengths mely ?

Answer 41

if you dont want to spend ours counting lines that could be easier

Answer 42

ill use the distance formula

Answer 43

glad to know it. however; for this one; you can simply count if you wanted to

Answer 44

yea thats works too

Answer 45

ok

Answer 46

as shown in my screenshot