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Calculate the mass of calcium carbonate present in a 50.00 mL sample of an aqueous calcium carbonate standard, assuming the standard is known to have a hardness of 75.0 ppm (hardness due to CaCO3). Also given is the density of the sample (0.9977g/mL) and the molar mass of CaCO3 (100.0g/mol).
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I honestly have no idea where to start on this problem
what does "75 ppm" mean in terms of concentration? can you express that in another form?
I'm not sure.
75 ppm = 75 mg/L can you try some more now?
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I don't think you need anything else but the conversion of ppm to mg/L
Thank you!
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