Graph the piece function using the values of a and b that you have found. You may graph by hand or use your calculator to graph and copy and paste into the document. -The problem numbers given will be drawn in an attached picture-
These are the numbers
\(f(x)= \begin{cases} 3-x&x<1\\ 2x^2+4x&1\le x<2\\ 5x-10&x\ge 2 \end{cases}\) rather
o.. just graph it :) I mean, you've covered piece-wise functions by now, or should have
That's the thing I don't know how to graph it.
well do you know how to graph 3-x? and \(2x^2+4x\)?
No I have no clue. I don't really understand this part of the chapter.
you'd graph 3-x first the constraints are, x < 1 so, once the graph, goes past 1, including 1 and above, erase all that because, greater than or 1, are not part of it
hmm lemme do a piece-wise quick say for example... to graph \(f(x)= \begin{cases} x^2&x>2\\ -x&x\le 2 \end{cases}\) so.. notice, we'd graph, the \(x^2\) but excluding the graph from below 2 and below 2, we'll include the linear "x" line so, the graph will look like |dw:1455322847841:dw|
notice, the slanted line INCLUDES 2, the parabola, does not because \(-x\quad x\le 2\)
also notice, because the parabolic equation, that is \(x^2\) doesn't include values below 2, or even 2, is "erased" to the left of 2
so .. just do those there graphs first :) and only include the graph, on the range provided
http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIzLXgiLCJjb2xvciI6IiNEMTE5MTkifSx7InR5cGUiOjAsImVxIjoiMnheMis0eCIsImNvbG9yIjoiIzMzMUVENCJ9LHsidHlwZSI6MCwiZXEiOiI1eC0xMCIsImNvbG9yIjoiIzJERDQxRSJ9LHsidHlwZSI6MTAwMCwid2luZG93IjpbIi04LjEyNSIsIjguMTI1IiwiLTUiLCI1Il19XQ-- look at the red one for example those are the 3 graphs, the red one is 3-x so x < 1 means -> erase it from 1 and further up, 1, 2, 3, 4, 5 ...... because only values of x being below 1 are used, that is, 0, -1, -2, -3, -4, -15, -10000.....
Your graph must consist of 3 parts, reflecting the 3 algebraic sub-functions that make up the whole function. If it'd be easier for you, graph each part, such as f1=3-x, as if the other two parts did not exist. Then, cut off all but the part of each graph specified by its domain. For example, graph f1= 3 - x for x < 1 only; erase the rest of this graph.
Can you please help me? @123AB456C
@jhonyy9
@sleepyjess
What is the domain of f1=3-x? You will have to identify 3 such domains to finish the entire problem. Answer: f1 is defined only for x < ?
I don't understand how to graph it into a piece wise function?
Please go back to my previous question and answer it.
f1= 3-x f1= 3-1 f1= 2
Maria, I asked you to find the SET of x values (which I call a "domain") for which f1=3-x is defined. Note that your computer work has produced one red graph. That's the graph of f1=3-x, right? But in the end your overall graph will have 3 parts. Once again, please go back tot he original problem statement and determine the interval (set of x values) for which f=f1=3-x.
"The first part of my overall graph is f1, defined as f1=3-x. This is not for all x, but only for the set of x values _____________________ " (Fill in the blank.)
Important: review jdoe's contribution; he listed the 3 parts of your graph and the sets of numbers for which the 3 parts are defined. His was the first reply you received.
Yes I understand that but when trying to graph a piece wise function you have to replace x with one.
can you please help? @Data_LG2
they are actually referring to the "domain" which is the one I circled here: http://i.imgur.com/ZlfhLXl.png You have to consider that. From your graph, the red one refers to 3-x... but the x values that you only need to consider is all values of x that is LESS THAN 1.. this means that the red graph will stop at x=1 with an open circle since one is not included. This will be the first part of your graph. Can you try to draw this part first?
where would the open circle go?
"red graph will stop at x=1 with an open circle since one is not included"
|dw:1455326790605:dw| Like this?
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