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Mathematics 13 Online
OpenStudy (princesssleelee):

Complex Numbers. Does anyone know how to do those types of problems?

OpenStudy (princesssleelee):

A student uses the quadratic formula to solve a quadratic equation and determines that one of the solutions is x = 4+ square root of -98 What are the values of a and b if this solution is written in the form x = a + bi, where a and b are real numbers?

OpenStudy (misty1212):

HI!!

OpenStudy (princesssleelee):

Hello!

OpenStudy (misty1212):

there is a real real easy way to do this, also an easy way, and a hard way q

OpenStudy (misty1212):

\[4+\sqrt{-98}\] can you write this in the form \(a+bi\) ?

OpenStudy (misty1212):

hint, \(98=2\times 49\)

OpenStudy (princesssleelee):

well i know sqrt of i = -1, correct? so somehow i would determine that sqrt of 98 and sqrt of -1 is ok no i cannnot lol

OpenStudy (misty1212):

\[\sqrt{-98}=\sqrt{49\times 2\times (-1)}=\sqrt{49}\sqrt2\sqrt{-1}\]

OpenStudy (misty1212):

so \(\sqrt{49}=?\)

OpenStudy (princesssleelee):

Alrighty 7

OpenStudy (misty1212):

good and what do you call \(\sqrt{-1}\)?

OpenStudy (princesssleelee):

i?

OpenStudy (misty1212):

right, what you said earlier

OpenStudy (misty1212):

you can't do anything with \(\sqrt2\) so just leave it \[4+\sqrt{-98}=4+7\sqrt{2}i\]

OpenStudy (princesssleelee):

a = 4 and b = seven square root of two end square root a = 4 and b = negative seven square root of two end square root a = 4 and b = square root of 14 end square root a = 4 and b = two square root of seven end square root

OpenStudy (misty1212):

now be careful here \[4+7\sqrt{2}i=a+bi\] so \(a=4,b=7\sqrt2\)

OpenStudy (misty1212):

guess it is the first one, sort of hard to read

OpenStudy (misty1212):

yeah that one

OpenStudy (princesssleelee):

I will post an actual photo of it lol. I have 4 other problems that i need help with.. some i am better at than this, would you mind helping?

OpenStudy (abdullahsadiqi):

@Misty1212 , Hats off ^_^

OpenStudy (princesssleelee):

OpenStudy (misty1212):

yeah first one

OpenStudy (anonymous):

choose a

OpenStudy (misty1212):

i have to run, i am sure you will get lots of help!

OpenStudy (princesssleelee):

Alrighty thank you! :)

OpenStudy (princesssleelee):

OpenStudy (princesssleelee):

I think that I've done this one correctly considering the answer is x=+-3i

OpenStudy (anonymous):

its a complex number

OpenStudy (anonymous):

which means imaginary number

OpenStudy (dayakar):

correct

OpenStudy (princesssleelee):

Yay! :)

OpenStudy (princesssleelee):

OpenStudy (dayakar):

do u have any idea

OpenStudy (princesssleelee):

Not really...

OpenStudy (dayakar):

\[\frac{ 4 }{ 4 } \pm \frac{ \sqrt{-25} }{ 4 }\]

OpenStudy (dayakar):

can u do it remaining part

OpenStudy (princesssleelee):

C....

OpenStudy (dayakar):

r u following

OpenStudy (princesssleelee):

4/4 =1 4 goes into 4, 1 time 4 goes into 25, 5 times 5/1=5

OpenStudy (princesssleelee):

Yes for the most part

OpenStudy (princesssleelee):

Did i configure that correctly?

OpenStudy (dayakar):

just find \[\sqrt{-25}\]value

OpenStudy (princesssleelee):

oh lol 5

OpenStudy (dayakar):

no it is 5i

OpenStudy (princesssleelee):

sorry i was going to correct myself, which isnt that the same as -5?

OpenStudy (dayakar):

now a+bi = \[1\pm 5i\] compare it

OpenStudy (dayakar):

sorry

OpenStudy (princesssleelee):

You lost me

OpenStudy (dayakar):

\[= 1\pm \frac{ 5 }{ 4 }i\]

OpenStudy (princesssleelee):

a=1 b=5/4? im not sure

OpenStudy (princesssleelee):

There isnt an 'i' in the answer choices

OpenStudy (dayakar):

exactly u r correct

OpenStudy (princesssleelee):

Making it answer choice A, correct?

OpenStudy (dayakar):

yes

OpenStudy (princesssleelee):

OpenStudy (dayakar):

do u know why i is missing in the answer

OpenStudy (princesssleelee):

Because it is + or -?

OpenStudy (princesssleelee):

or because it cancels out

OpenStudy (dayakar):

no we r comparing a + bi with given problem u can easily find a but b is coefficient of i [ mean the number before the i] that's why we don't have i

OpenStudy (princesssleelee):

Oh Lol duahh, lol thank you

OpenStudy (anonymous):

lol nice

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