the vertical height v, in feet of a snowboarder jumping off of an overhang can be modeled by the functions h(t)= 15-10t-16t^2, where 15 is the initial height (in feet) of the over hang, -10 is the initial vertical velocity (in feet per second) and t is the time (in seconds)

A. How long does it take the snowboarder to land after jumping off the overhang?

B. If the snowboarder horizontal velocity is 10 feet per second, how far from the base of the overhang will she land?

Question

the vertical height v, in feet of a snowboarder jumping off of an overhang can be modeled by the functions h(t)= 15-10t-16t^2, where 15 is the initial height (in feet) of the over hang, -10 is the initial vertical velocity (in feet per second) and t is the time (in seconds)

A. How long does it take the snowboarder to land after jumping off the overhang?

B. If the snowboarder horizontal velocity is 10 feet per second, how far from the base of the overhang will she land?

study312 · Answer

@mathmale

serenity74 · Answer

@imqwerty @inkyvoyd @hadleycornish @Nafa78

freckles · Answer

for him to land... that means he is on the ground
that means h is 0
so just find t for when h is 0

mathmale · Answer

the vertical height v, in feet of a snowboarder jumping off of an overhang can be modeled by the functions h(t)= 15-10t-16t^2  When does this guy hit the ground?  When on the ground, his height, h(t), is zero.  Thus, set 15-105-16t^2 equal to zero and solve for time, t.  Time, t, has to be positive to make sense.

How would you go about solving 15-10t-16t^2=0 for t?