OpenStudy (anonymous):

help

1 year ago
OpenStudy (anonymous):

@jhonyy9

1 year ago
OpenStudy (anonymous):

@briannabug

1 year ago
OpenStudy (anonymous):

HELP

1 year ago
OpenStudy (briannabug):

Yes?

1 year ago
OpenStudy (anonymous):

OK

1 year ago
OpenStudy (anonymous):

\[X ^{2}=256\]

1 year ago
OpenStudy (anonymous):

WHAT DO I DO

1 year ago
OpenStudy (563blackghost):

To solve you would square root 256... \[x=\sqrt{256}\]

1 year ago
OpenStudy (anonymous):

um

1 year ago
OpenStudy (anonymous):

idk

1 year ago
OpenStudy (563blackghost):

When simplifying x whenever you have a \(\Large{x^{2}}\) you would do the opposite so you would square root the number....basically you would find a number that multiples itself to equal \(\Large\color{red}{256}\)

1 year ago
OpenStudy (anonymous):

16

1 year ago
OpenStudy (563blackghost):

Correct ^^

1 year ago
OpenStudy (563blackghost):

So.... \(\Huge\color{red}{x=16}\)

1 year ago
OpenStudy (anonymous):

would it be a pative and a netive

1 year ago
OpenStudy (anonymous):

positive and negative?

1 year ago
OpenStudy (jhonyy9):

yes nicolai you see it right x^2 = a x_1,2 = +/-sqrta

1 year ago
OpenStudy (anonymous):

ok thanks i have more if you could hepl

1 year ago
OpenStudy (anonymous):

@jhonyy9

1 year ago
OpenStudy (anonymous):

ok um

1 year ago
OpenStudy (anonymous):

flutter this pellet i am going to ned help tommrow i passed

1 year ago