If Mo is the mass of oxygen isotope ,Mp and Mn are the masses of a proton and a neutron respectively the nuclear binding energy of isotope is
@Vincent-Lyon.Fr pls.help
@astrophysics pls...help... @rvc @priyar
hey hi please refer to this link : http://hyperphysics.phy-astr.gsu.edu/hbase/nucene/nucbin.html
@rvc i know this....bt what i want to say is that i m having a -ve sign in the ans
I know dat nuclear binding energy is calculated by difference in mass of reactants n products...
Multiplied vid c^2
Like my ans is (8Mp+9Mn -Mo)c^2
N their ans is -ve of it..
hmm..wait @ganeshie8 help
Did u get my doubt ??
m confused
Confused in -ve sign or d whole ans...
@rvc plss..reply...
@IrishBoy123 help me
So what's bothering you is not the magnitude, but the negative sign?
Yep ...@parthkohli...this is nuclear energy n here signs are meant to be of gr8 meaning
OK, binding energy whenever attractive forces are involved is treated to be of a negative sign. We assume that zero potential energy is when all masses are held at infinite separation. A way to understand this is you'll have to do positive work against the attractive force to bring them to infinite separation.\[\rm E_{binding}+\text{some positive work} = E_{infinity}= 0\]\[\Rightarrow \rm E_{binding} = - (\text{some positive work)} = \text{some negative number}\]So that is why binding energy in case of attractive forces is negative.
@parthkohli it has been clearly mentioned in binding energy that it is equal to (mass of reactants-mass of products)*c^2
Err modern physics. -_-
Yep @ParthKohli is correct
`-ve` sign means ATTRACTIVE FORCE.
Ok @samigupta8 i got your doubt
First tell me what is binding energy ?
Mass of protons and neutrons forming nucleus is always less than mass of nucleus ...this thing dat is d difference between them appears as mass defect which when multiplied vid c^2 gives us binding energy
@parthkohli yeah...it'zz dat nuclear physics .....
Sorry greater than....
what mayank said is that the negative sign is because it is an attractive force
But if u go through any of the books u will find whatever b d case v always take binding energy as this only...the definition posted above...by me
It's always an attractive force bt i never came up vid d sign reversal jst like in dis problem... So here is d major doubt of dis problem... I m greatly concerned by dis sign...nothing else...
maybe it means the resulting isotope is unstable?
Bt it's never this way @baru How can u arrive at it so easily ?
yes we usually take binding energy to be positive.
@priyar whom r u supporting here?
u
i have no idea... i'm just guessing
@baru it's like that i hve never came across any such thing before so i can't swallow it so easily dat it can be -ve of what i m getting...
Don't you all think that there needs to be d ans which i m telling u all...i seriously donno whether my doubt is rubbish or not Bt guys...i m literally for sure confused in it...
binding energy is the energy that holds the protons and neutrons together.. to break the nucleus to its constituents we need to supply energy equal to the binding energy..otherwise its the other way around.. in problems we usually find the magnitude which is same in both cases..
i dont really know... i'm just going by whatever info is on this thread u said that the nucleus is lighter than the sum of its constiutents so in the formula (mass of reactants-mass of products)*c^2 if reactants mean constituents and produduct means nucleus, then the answer is always positive
Correct that's what is my argument here...why ans is -ve den
yes binding energy is more properly defined as: "Nuclear binding energy is the energy required to split a nucleus of an atom into its component parts: protons and neutrons, or, collectively, the nucleons. " and, the binding energy of nuclei is always a positive number, since all nuclei require net energy to separate them into individual protons and neutrons.
So as i said before... we supply an energy equal to the binding energy to split the nucleus... and that is also the definition of nuclear binding energy so we take it to a POSITIVE quantity always which is also justified by Einstein's eq
So basically v all r ending up vid same conclusion ryt....in different manners ....lol ...
yes..our definition is like that..a bit confusing...but we always define it as "energy required" which stand for +ve.. (in my opinion).. i haven't come across a negative binding energy so far..
Thanks.....bt dis is sumthing i know already i wud like to know if their ans is correct or mine.....plss...if any of u cum across d reason of it. .pls do tell me ....bcz dis is sumthing dat pesters me to the core
@samigupta8 First read the definition ! You can notice that BINDING ENERGY IS AN ATTRACTIVE FORCE.It is natural. So, why we always use `-ve`sign. Take an example:- Centripetal force is also acts at centre.So it is attractive in nature. So,why can't we add `-ve`sign to it ?
yep @mayankdevnani i agree
thank you !
So @mayankdevnani you want to say that it should occur in every question .. isn't it??
yep!
like centripetal force
Always an attractive force. It is understood.
@mashy
There is nothing like confusion.
Try to understand with easiest example like centripetal force. Try to co-relate with it.
@mayankdevnani haven't u done questions based on this ....where v need to calculate binding energy n it has to be sum of nucleons-sum of nucleus..... Pls...@mayankdevani u try to understand my point of view.....sorry if u r feeling dat i m trning out to be rude
i have done many questions
Then each time u did the same thing told by you...or as told by me
first tell me mass of nucleus is greater or mass of nucleons
Mass of nucleons
and what is the formula of BE
N so mass defect is mass of nucleons- mass of nucleus
Mass defect *c^2
why would you use mass defect=mass of nucleons-mass of nucleus ?
why not this :- mass defect=mass of nucleus-mass of nucleons
wait wait @Michele_Laino !!!! help
Yrr mayank ...ruko hangouts kholo apna i will send sumthing
okay !
@rvc michele sir is a good friend of mine. Like we are BESTIEEES
lol ikr
you know ! wow
is the isotope \[\huge _8^{17}{\text{O}}\]?
nope
Yep
Yehi toh h ...
probably \[\large \bf _8^{18}O\]
Mayank @michele sir is ryt ...
mine is correct too
Arey i m talking about d present question
first answer my question
in that case the requested binding energy is: \[\Large BE = \left\{ {\left( {8{m_p} + 10{m_n}} \right) - {m_{isotope}}} \right\}{c^2}\] since we have 8 protons and 18-8=10 neutrons
why would you use mass defect=mass of nucleons-mass of nucleus ? why not this :- mass defect=mass of nucleus-mass of nucleons?
Vicg question
Exactly @michele_laino sir...
of course if the isotope is: \[\huge _8^{17}{\text{O}}\] then the answer of @samigupta8 is correct!
Thank you...@michele_laino n obviously d isotope mentioned in question is dis one only
lol atlast !
@mayankdevnani please refer to my tutorial: http://openstudy.com/study#/updates/569003b1e4b09cb8736d02b5
thank you so much sir! m glad that you helped us
So @Michele_laino sir my ans is correct ryt... Bt in d ans key it is giving -ve sign in front of d expression u came with finally
the minus sign depends on the definition we use
How?
some authors define the binding energy in this way: \[\Large - BE = \left\{ {\left( {8{m_p} + 10{m_n}} \right) - {m_{isotope}}} \right\}{c^2}\]
Seriously ?? Like then whom to trust upon ??
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