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OpenStudy (samigupta8):

If Mo is the mass of oxygen isotope ,Mp and Mn are the masses of a proton and a neutron respectively the nuclear binding energy of isotope is

OpenStudy (samigupta8):

@Vincent-Lyon.Fr pls.help

OpenStudy (samigupta8):

@astrophysics pls...help... @rvc @priyar

rvc (rvc):

hey hi please refer to this link : http://hyperphysics.phy-astr.gsu.edu/hbase/nucene/nucbin.html

OpenStudy (samigupta8):

@rvc i know this....bt what i want to say is that i m having a -ve sign in the ans

OpenStudy (samigupta8):

I know dat nuclear binding energy is calculated by difference in mass of reactants n products...

OpenStudy (samigupta8):

Multiplied vid c^2

OpenStudy (samigupta8):

Like my ans is (8Mp+9Mn -Mo)c^2

OpenStudy (samigupta8):

N their ans is -ve of it..

rvc (rvc):

hmm..wait @ganeshie8 help

OpenStudy (samigupta8):

Did u get my doubt ??

rvc (rvc):

m confused

OpenStudy (samigupta8):

Confused in -ve sign or d whole ans...

OpenStudy (samigupta8):

@rvc plss..reply...

rvc (rvc):

@IrishBoy123 help me

Parth (parthkohli):

So what's bothering you is not the magnitude, but the negative sign?

OpenStudy (samigupta8):

Yep ...@parthkohli...this is nuclear energy n here signs are meant to be of gr8 meaning

Parth (parthkohli):

OK, binding energy whenever attractive forces are involved is treated to be of a negative sign. We assume that zero potential energy is when all masses are held at infinite separation. A way to understand this is you'll have to do positive work against the attractive force to bring them to infinite separation.\[\rm E_{binding}+\text{some positive work} = E_{infinity}= 0\]\[\Rightarrow \rm E_{binding} = - (\text{some positive work)} = \text{some negative number}\]So that is why binding energy in case of attractive forces is negative.

OpenStudy (samigupta8):

@parthkohli it has been clearly mentioned in binding energy that it is equal to (mass of reactants-mass of products)*c^2

Parth (parthkohli):

Err modern physics. -_-

OpenStudy (mayankdevnani):

Yep @ParthKohli is correct

OpenStudy (mayankdevnani):

`-ve` sign means ATTRACTIVE FORCE.

OpenStudy (mayankdevnani):

Ok @samigupta8 i got your doubt

OpenStudy (mayankdevnani):

First tell me what is binding energy ?

OpenStudy (samigupta8):

Mass of protons and neutrons forming nucleus is always less than mass of nucleus ...this thing dat is d difference between them appears as mass defect which when multiplied vid c^2 gives us binding energy

OpenStudy (samigupta8):

@parthkohli yeah...it'zz dat nuclear physics .....

OpenStudy (samigupta8):

Sorry greater than....

rvc (rvc):

what mayank said is that the negative sign is because it is an attractive force

OpenStudy (samigupta8):

But if u go through any of the books u will find whatever b d case v always take binding energy as this only...the definition posted above...by me

OpenStudy (samigupta8):

It's always an attractive force bt i never came up vid d sign reversal jst like in dis problem... So here is d major doubt of dis problem... I m greatly concerned by dis sign...nothing else...

OpenStudy (baru):

maybe it means the resulting isotope is unstable?

OpenStudy (samigupta8):

Bt it's never this way @baru How can u arrive at it so easily ?

OpenStudy (priyar):

yes we usually take binding energy to be positive.

OpenStudy (samigupta8):

@priyar whom r u supporting here?

OpenStudy (priyar):

u

OpenStudy (baru):

i have no idea... i'm just guessing

OpenStudy (samigupta8):

@baru it's like that i hve never came across any such thing before so i can't swallow it so easily dat it can be -ve of what i m getting...

OpenStudy (samigupta8):

Don't you all think that there needs to be d ans which i m telling u all...i seriously donno whether my doubt is rubbish or not Bt guys...i m literally for sure confused in it...

OpenStudy (priyar):

binding energy is the energy that holds the protons and neutrons together.. to break the nucleus to its constituents we need to supply energy equal to the binding energy..otherwise its the other way around.. in problems we usually find the magnitude which is same in both cases..

OpenStudy (baru):

i dont really know... i'm just going by whatever info is on this thread u said that the nucleus is lighter than the sum of its constiutents so in the formula (mass of reactants-mass of products)*c^2 if reactants mean constituents and produduct means nucleus, then the answer is always positive

OpenStudy (samigupta8):

Correct that's what is my argument here...why ans is -ve den

OpenStudy (priyar):

yes binding energy is more properly defined as: "Nuclear binding energy is the energy required to split a nucleus of an atom into its component parts: protons and neutrons, or, collectively, the nucleons. " and, the binding energy of nuclei is always a positive number, since all nuclei require net energy to separate them into individual protons and neutrons.

OpenStudy (priyar):

So as i said before... we supply an energy equal to the binding energy to split the nucleus... and that is also the definition of nuclear binding energy so we take it to a POSITIVE quantity always which is also justified by Einstein's eq

OpenStudy (samigupta8):

So basically v all r ending up vid same conclusion ryt....in different manners ....lol ...

OpenStudy (priyar):

yes..our definition is like that..a bit confusing...but we always define it as "energy required" which stand for +ve.. (in my opinion).. i haven't come across a negative binding energy so far..

OpenStudy (samigupta8):

Thanks.....bt dis is sumthing i know already i wud like to know if their ans is correct or mine.....plss...if any of u cum across d reason of it. .pls do tell me ....bcz dis is sumthing dat pesters me to the core

OpenStudy (mayankdevnani):

@samigupta8 First read the definition ! You can notice that BINDING ENERGY IS AN ATTRACTIVE FORCE.It is natural. So, why we always use `-ve`sign. Take an example:- Centripetal force is also acts at centre.So it is attractive in nature. So,why can't we add `-ve`sign to it ?

rvc (rvc):

yep @mayankdevnani i agree

OpenStudy (mayankdevnani):

thank you !

OpenStudy (samigupta8):

So @mayankdevnani you want to say that it should occur in every question .. isn't it??

OpenStudy (mayankdevnani):

yep!

OpenStudy (mayankdevnani):

like centripetal force

OpenStudy (mayankdevnani):

Always an attractive force. It is understood.

rvc (rvc):

@mashy

OpenStudy (mayankdevnani):

There is nothing like confusion.

OpenStudy (mayankdevnani):

Try to understand with easiest example like centripetal force. Try to co-relate with it.

OpenStudy (samigupta8):

@mayankdevnani haven't u done questions based on this ....where v need to calculate binding energy n it has to be sum of nucleons-sum of nucleus..... Pls...@mayankdevani u try to understand my point of view.....sorry if u r feeling dat i m trning out to be rude

OpenStudy (mayankdevnani):

i have done many questions

OpenStudy (samigupta8):

Then each time u did the same thing told by you...or as told by me

OpenStudy (mayankdevnani):

first tell me mass of nucleus is greater or mass of nucleons

OpenStudy (samigupta8):

Mass of nucleons

OpenStudy (mayankdevnani):

and what is the formula of BE

OpenStudy (samigupta8):

N so mass defect is mass of nucleons- mass of nucleus

OpenStudy (samigupta8):

Mass defect *c^2

OpenStudy (mayankdevnani):

why would you use mass defect=mass of nucleons-mass of nucleus ?

OpenStudy (mayankdevnani):

why not this :- mass defect=mass of nucleus-mass of nucleons

rvc (rvc):

wait wait @Michele_Laino !!!! help

OpenStudy (samigupta8):

Yrr mayank ...ruko hangouts kholo apna i will send sumthing

OpenStudy (mayankdevnani):

okay !

OpenStudy (mayankdevnani):

@rvc michele sir is a good friend of mine. Like we are BESTIEEES

rvc (rvc):

lol ikr

OpenStudy (mayankdevnani):

you know ! wow

OpenStudy (michele_laino):

is the isotope \[\huge _8^{17}{\text{O}}\]?

OpenStudy (mayankdevnani):

nope

OpenStudy (samigupta8):

Yep

OpenStudy (samigupta8):

Yehi toh h ...

OpenStudy (mayankdevnani):

probably \[\large \bf _8^{18}O\]

OpenStudy (samigupta8):

Mayank @michele sir is ryt ...

OpenStudy (mayankdevnani):

https://en.wikipedia.org/wiki/Isotopes_of_oxygen yep there are 3

OpenStudy (mayankdevnani):

mine is correct too

OpenStudy (samigupta8):

Arey i m talking about d present question

OpenStudy (mayankdevnani):

first answer my question

OpenStudy (michele_laino):

in that case the requested binding energy is: \[\Large BE = \left\{ {\left( {8{m_p} + 10{m_n}} \right) - {m_{isotope}}} \right\}{c^2}\] since we have 8 protons and 18-8=10 neutrons

OpenStudy (mayankdevnani):

why would you use mass defect=mass of nucleons-mass of nucleus ? why not this :- mass defect=mass of nucleus-mass of nucleons?

OpenStudy (samigupta8):

Vicg question

OpenStudy (samigupta8):

Exactly @michele_laino sir...

OpenStudy (michele_laino):

of course if the isotope is: \[\huge _8^{17}{\text{O}}\] then the answer of @samigupta8 is correct!

OpenStudy (samigupta8):

Thank you...@michele_laino n obviously d isotope mentioned in question is dis one only

rvc (rvc):

lol atlast !

OpenStudy (michele_laino):

@mayankdevnani please refer to my tutorial: http://openstudy.com/study#/updates/569003b1e4b09cb8736d02b5

rvc (rvc):

thank you so much sir! m glad that you helped us

OpenStudy (samigupta8):

So @Michele_laino sir my ans is correct ryt... Bt in d ans key it is giving -ve sign in front of d expression u came with finally

OpenStudy (michele_laino):

the minus sign depends on the definition we use

OpenStudy (samigupta8):

How?

OpenStudy (michele_laino):

some authors define the binding energy in this way: \[\Large - BE = \left\{ {\left( {8{m_p} + 10{m_n}} \right) - {m_{isotope}}} \right\}{c^2}\]

OpenStudy (samigupta8):

Seriously ?? Like then whom to trust upon ??

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