stretch the asymptotes and graph the function y=5/x-2+3
Please use parentheses to indicate which math operations are to be performed first. Did you mean 5 / (x-2) or did you mean 5 / x ? Also, what do you mean by "stretch the asymptotes?"
5/(x-2)
@mathmale
OK. We have y = 5 / (x+2) +3. First: How does one locate asymptotes?
I'm really lost with this. Can you break it down for me?
Let's build upon what you already know. What is an "asymptote?" Where have you seen asymptotes before?
i just saw them once in a lesson
they werent really explained
OK. We have y = 5 / (x+2) +3 Next time, please ask questions about whatever you found to be poorly explained. That way someone could help you more efficiently. In the above equation, what would happen if x = - 2?
2?
Another way in which to ask this same question: Can we let x=-2 in the given equation? Try it and share your results.
y = 5 / (-2+2) +3
That's right. Can you take the math any further than that?
y = 5 / (-2+2) +3 y = 5 /+3
Actually, it'd be\[y=\frac{ 5 }{ 0 }+3\] Make a judgment. Is this OK or not OK? Why?
idk what would make it not ok or ok.
y = 5 / (-2+2) +3 y = 5/0 +3
Have you heard the phrase, "division by zero is .... "?
I havent
Division by zero is undefined. We can't divide by zero, period. This limitation means that you cannot let x=2. Why? Because then the denominator of 5 / (x-2) would be zero, which is not permitted. We'll need to come back to this later. But for now, having identified the x value for which the function is undefined, we can write, "the vertical asymptote of the graph of this function is the vertical line x=2. You could draw a set of coordinate
axes and then draw the vertical line x=2 as well. Your graph can NOT cross this vertical axis.
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Once again, your graph can NOT cross the vertical line x=2, which is your "vertical asymptote."
so that is when lines to not cross?
its kind of coming back to me now i thought it was when lines dont cross the axis
I'm sorry, Dani, but I need to get off the Internet now. But I'd be glad to continue this discussion. Tag me later on today, or repost this question. To answer you question: It's the graph that can't cross the verticql asymptote, x=2. I will go into that further when we reconnect. For now, I challenge you to look at the equation given and try to figure out what happens to y as x becomes larger and larger. This is how you determine your "horiz. asymptote."
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