Solve 2x^2 - 8x = -7. I think by completing the square
@Vijeya3 any thoughts?
oh alright thank you so much !
@Everly what is the first step ?
you take the square root right?
no i think take the -7 on the left side and how will get than the quadratic ?
take the -7 and do what?
just than see what you get ?
@Vijeya3 Attention please here in openstudy we dont give to asker directly right answer just we try help step by step - ok ?
I'm still unclear of which route to take, I don't know how to get to the trinomial either
@mathmale your opinion please about this ?
I understand taking the square root, completing the square, quad formula etc
im going to take the quadratic formula i think, and yes ax^2+bx+c=0, right?
i think so but doesn't the x^2 coefficient have to equal to 1?
i tried to divide 2 but that left me with a fraction i didnt know how to solve
are we starting from before or after we add 7 to both sides?
yeah to make it equal to 0
a quadratic formula? 2x^2 - 8x +7 = 0
yes i did it a while ago but forgot it, (x+4) (x-4) ??
so can you explain the method then?
x≈2.70710678,1.29289322
I understand all of that trust me I do and I've done other expressions but its just this one I'm stuck on
@RhondaSommer
\[2x^2-8x + 7 = 0\] this is what you know right?
@Vijeya3 i was personally asked to help. please do not interfere while I teach.
Yes, but I don't know where to go after it. I can't use the sum-product, it doesn't make sense
medal?
okay Divide each side by '2'.
sorry each coefficient
because you want the coefficient of x^2 to be 1
i did that but i ended up with the fraction 7/2 (3.5) x^2+4+7/2 (3.5) = 0
yup :) you need that to continue
\[ x^2 - 4x + 3.5= 0\]
now; you need to subtract 3.5 from both sides :)
Really? I was trying to complete the square... okay so x^2 +4 = 3.5 what do I do next?
\[x^2 + 4 = -3.5\] not just 3.5 because you subtracted
Oh sorry, I wrote that but didn't type, do I factor?
So now your x term is -4x. Take half its coefficient (-2). Square it (4) and add it to both sides.
\[x^2 + 4 + 4 = -3.5 +4\]
How did you know to do that? What method is that?
completing the square. \[x^2 + 4x + 4 = -3.5 + 4\]
That's the part I'm confused at, because in order to complete square the coefficient of x should be equal to 2a
Which I know see is 2(2) = 4
now*
and our x coefficient is 2 so does that make sense now?
Yup! So add 4 to both sides and get x^2 +8 = 7.5, correct?
-3.5 + 4 = 0.5. i also miss wrote it at first \[x^2+4x+4=-3.5+4\]
This is making so much sense now thank you, okay so , I subtract for now from both sides?
four*
nope simplify. ^_^ \[x^2+4x+4=0.5\]\[x^2+4x+4\] is a perfect square...so simplify it ^_^ then tell me what it is :)
Yup! I just caught on, x^2 + 4x + 4 (x+2)^2 I think, not too sure
whoops! i keep writing it wrong. my mistake. \[x^2-4x+4\] simplify that
i made that mistake waaay earlier. it should have been -4x the entire time. luckily that doesnt affect what we have done so far.
instead; it will be (x-2)(x-2) = the square root of ±0.5
but would that four we added now have to be subtracted x^2 - 4x -4 ?
no because that is a perfect square ^_^
(x-2) = -0.70710678118654752440084436210485 and (x-2) = 0.70710678118654752440084436210485
simplify those :)
So 2(a) is always 2(a) no matter if x is a negative ?
yup :)
1.2928932188134524755991556378952 2.7071067811865475244008443621048 when simplified :) does that make sense?
Sorry my computer froze, I'm not sure if I understand how to simplify those. And my options are way different too!
thats strange. what are your options
simplify it :)
1.4142135623730950488016887242097 is square root of 2
and it has to be positive 2 not negative because of (x-2) add two and thats part of your answer
so i belive it is d :) √2 /2 is the same as √0.5
:) make sense?
I kind of understand that but what do you mean by (x-2) add 2 is a part of my answer?
no. x-2 = 0 you have to add 2 two both sides to get x alone
its just to get x alone. your answer is simply d
::)
I kind of understand that but what do you mean by (x-2) add 2 is a part of my answer?
Oh!!!! Wow I finally get it! I've been on this question since 9 AM and it's now almost 11:30AM. I couldn't figure it out without you @RhondaSommer thank you so so so much :)
no problemo ^_^
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