How is the wavelength of an electromagnetic wave related to the energy of the wave?
Energy and wavelength are not related
Energy remains constant as wavelength changes
As wavelength increases, energy decreases

As wavelength increases, energy increases

Question

How is the wavelength of an electromagnetic wave related to the energy of the wave?
 Energy and wavelength are not related
Energy remains constant as wavelength changes
As wavelength increases, energy decreases

 As wavelength increases, energy increases

kimberly_pr · Answer

@Loser66   @pooja195

kimberly_pr · Answer

@Mehek14

kimberly_pr · Answer

@whpalmer4   @radar

aaronq · Answer

Shorter wavelengths have more energy

aaronq · Answer

than longer ones

kimberly_pr · Answer

Thank you! And can I ask you one more question? @aaronq

photon336 · Answer

$$E = \frac{ hc }{ \lambda  }$$

photon336 · Answer

@Kimberly_PR consider this. see how wavelength = lambda is in the denominator? the smaller the wavelength the higher the value for E will be in the equation. so the two are inversely proportional

kimberly_pr · Answer

That makes so much sense, thanks :)

photon336 · Answer

you see what's going on in that fraction right? @Kimberly_PR

kimberly_pr · Answer

The big E stands for the amount of energy, and like you said, the wavelength is in the denominator, no?

photon336 · Answer

h = placks constnat and c = speed of light  both constants

kimberly_pr · Answer

Oh ok, so the constants are the numerators. I get it now. :)

photon336 · Answer

this is something you should remember because it applies to other formulas too

kimberly_pr · Answer

I have a really bad memory, lol, but I'll write it down for now. And can I ask you one more question?

photon336 · Answer

the smaller our numbers are in our denominator say a fraction, the bigger our result will be. take a look @this 

$$\frac{ 1 }{ (0.5) } = 2, vs \frac{ 1 }{ 2} = 0.5 $$

photon336 · Answer

@Kimberly_PR yeah sure. but remember don't just memorize, because you'll easily forget it. what's your other question?

kimberly_pr · Answer

What would be the most likely charge of an ion formed from an atom with the electron configuration:
1s22s22p63s2

+1

 -1

 +2

 -2

photon336 · Answer

do you know what this means? 

$$1s^22s^22p^63s^2$$

kimberly_pr · Answer

Yeah, it's an electron configuration, it's like a guide that tells you where on the periodic table is a certain element, right?

photon336 · Answer

that's correct

photon336 · Answer

the number in-front tells us the principle quantum number or the period that it is in the periodic table. the number on the top tells us how many electrons it has. 

count the number of electrons by adding up the exponents i.e. the numbers found on top. 

what do we get?

kimberly_pr · Answer

12

photon336 · Answer

alright, now we know that there are 12 electrons, what element is that?

kimberly_pr · Answer

Neon? I'm not too sure

photon336 · Answer

remember protons = number of electrons look for an atomic number of 12

kimberly_pr · Answer

Magnesium?

kimberly_pr · Answer

@Photon336  Nooo, don't leave yet please :/

photon336 · Answer

correct

photon336 · Answer

now. Magnesium is a metal or non metal?

kimberly_pr · Answer

An alkaline metal, right?

photon336 · Answer

yep. so remember metals like to lose electrons while non metals like to gain them. they like to lose electrons to get to a noble gas configuration. Ask yourself this will magnesium lose or gain electrons and if so, what noble gas configuration will result

kimberly_pr · Answer

Since magnesium likes to lose electrons would it be a positive or negative charge?

photon336 · Answer

loss of electrons results in a positive charge :)

photon336 · Answer

magnesium has 12 right, so it likes to lose electrons. what noble gas would it resemble if it lost its electrons?

kimberly_pr · Answer

The answer is +2 right?

photon336 · Answer

yes :)

kimberly_pr · Answer

Yayyy, thank you so much for all your help and explanations :))

photon336 · Answer

no problem anytime!