Can anyone help me divide a rational expression? Find the Quotient and Simplify. 7x^7 over 3x^5 divided by 14x over 9x^3
if you divide by a fraction, you can "flip it" and multiply by it. Can you do that for this problem ?
Yes, I know I have to flip the second fraction. I'm just not sure how to find the common denominator
you don't need a common denominator when multiplying (or dividing) you should get \[ \frac{7x^7}{3x^5} \cdot \frac{9x^3}{14x} \] when multiplying you multiply top times top and bottom times bottom but you can first divide (it's usually easier)
order can be changed when multiplying for example, the top can be written as 7*9 * x^7 * x^3 and at the bottom 14*3*x^5*x \[ \frac{ 7 \cdot 9 \cdot x^7 \cdot x^3}{14 \cdot 3 \cdot x^5 \cdot x}\] and you can divide the numbers
you can "split apart" that fraction, and write it like this \[ \frac{7}{14} \cdot \frac{9}{3} \cdot \frac{x^7 \cdot x^3}{x^5\cdot x} \]
people don't usually bother, but it might make it easier to see how to simplify the numbers can you simplify 7/14 ?
yes that would be 1/2
For the x's you use the idea that \[ \frac{x}{x} = 1\] anything divided by itself is 1 so if you see x^7 (which is short for x*x*x*x*x*x*x) and you see x^5 in the bottom: x*x*x*x*x you can see 5 of the x's in the bottom can divide into 5 in the top (you get 1*1*1*1*1) leaving x*x up top yes 7/14 is ½ what about 9/3 ?
9/3 would be \[\frac{ 1 }{ 3 }\]
other way round , right ?
oops! yes, other way around
ok, make a note: the numbers simplify to ½ * 3 or 3/2 can you do the x's ?
I think so. Would the final answer be 3x^11 over 2^6?
how did you get that ?
ignore the numbers and look just at \[ \frac{x^7 x^3}{x^5x} \]
Don't you add the exponents?
with all those x's it's a pain to type out, so let's do a small problem \[ \frac{x^3}{x} \] as you know x^3 means x*x*x \[ \frac{x\cdot x\cdot x}{x} \] and as you know we can make that into separate fractions \[ \frac{x}{x} \cdot \frac{x}{1}\cdot \frac{x}{1} \] notice you multiply top times top and bottom times bottom we get what we started with
we can simply by know x/x is 1 and 1 times anything is the anything in other words we get \[ \frac{x}{1}\cdot \frac{x}{1} = \frac{x^2}{1}= x^2 \] the fast way is to subtract the bottom exponent from the top exponent 3-1= 2 and write x^2 right away
yes, you can add exponent when multiplying x^2 * x^2 means x*x * x*x or in short hand x^4 the fast way is to do 2+2 to get 4 for the exponent. so you could do the top and get x^(7+3) = x^10 and the bottom you get x^(5+1) = x^6 and you can divide x^6 into x^10 to get x^4
Ok I'm getting a little lost now
try this one: \[ \frac{x}{x} \] what does the simplify to ?
1
and you might know if we put in an exponent of 1 x^1 = x (we don't usually bother to show an exponent if it's one) \[ \frac{x^1}{x^1} \] if we subtract the exponents top - bottom : 1- 1=0 we get \[ \frac{x^1}{x^1} =x^0 =1\]
I'm forgetting what my original problem is now
anything to the 0 power is 1. (make a note of that... it may not be obvious)
we will do you problem in just a minute can you simplify \[ \frac{x\cdot x}{x} \] ?
notice it's the same as simplifying \[ \frac{x}{x} \cdot \frac{x}{1} \]
it would still be 1
or x^2 over 1x
x/x is 1 you can "replace" the x/x with 1, but you would then have \[ \frac{x}{x} \cdot \frac{x}{1} =1 \cdot \frac{x}{1} \]
This is the idea you want to learn \[ \frac{x\cdot x}{x} = \frac{x}{x} \cdot \frac{x}{1} = 1 \cdot \frac{x}{1} =\frac{x}{1}\]
I'm running out of time and just need the answer or at least simple steps to the answer
add the exponents in the top what do you get ?
10
now do the same in the bottom
6
and because you are dividing do 10 - 6 to get the exponent for x
4
in other words x^4 with the numbers you get \[ \frac{3x^4}{2} \]
and that is found by multiplying the fractions and then simplifying them? Thank you for all your help
You can also reduce each fraction before dividing them. \(\Large \dfrac{7x^7}{3x^5} \div \dfrac{14x}{9x^3} \) \(\Large =\dfrac{7x^2}{3} \div \dfrac{14}{9x^2} \) \(\Large =\dfrac{7x^2}{3} \times \dfrac{9x^2}{14} \) \(\Large =\dfrac{7 \times 3 \times 3 x^4}{3 \times 2 \times 7} \) \(\Large =\dfrac{\cancel{7} \times \cancel{3} \times 3 x^4}{\cancel{3} \times 2 \times \cancel{7}} \) \(\Large =\dfrac{3 x^4}{ 2}\)
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