The thickness of a kerosene spill is 1.2 mm. The spill is .79 miles in diameter. Kerosene has a density of .82 g/cc. Assuming that the spill is uniform in thickness and is shaped in a circle, how much kerosene, volume and mass, was spilled?

Question

anonymous · Answer

Could someone please help me?

anonymous · Answer

I think I know what to do, and it has to do with the density/mass/volume formulas

anonymous · Answer

I also know that the thickness, is the H in the L x W x H = Volume

anonymous · Answer

So I'd have to find the L and the W, or find the mass and then divide it by the density

anonymous · Answer

First, Find the volume of the spill, in cc's. (cm^3).

anonymous · Answer

Ok, how would I be able to do that?

anonymous · Answer

I know I must use the formula for volume of a sphere or something right?

anonymous · Answer

Get the radius from the given diameter and then solve for volume?

anonymous · Answer

what shape is the oil spill?

anonymous · Answer

a circle

anonymous · Answer

The shape of the spill is a circle, but is there a formula to find the volume of a circle?

anonymous · Answer

with height,

anonymous · Answer

A cylinder.

anonymous · Answer

Oh I knew it! I just wasn't sure if that was the right one

anonymous · Answer

I think its a safe assumption

anonymous · Answer

So I have to use the formula V=πr2h

anonymous · Answer

and H would be the thickness right?

anonymous · Answer

$$\pi r^2h$$

anonymous · Answer

yep

anonymous · Answer

Well yeah

anonymous · Answer

so it would be V = V=π .39^2 (1.2)

anonymous · Answer

gtg.... be sure to be careful with units

anonymous · Answer

Oh Ok! thank you for the help!

anonymous · Answer

And I know it must be in gallons, so I'll keep that in mind!