f(x) =-4x3 + 7x Determine if its Even,odd, neither
What do u think?
don't we plug -x for x?
yep
yes
so what do u think now
so we get umm -4(-x)^3+7(-x) so neither?
it maybe help you to know (-x)^odd =-x^odd while (-x)^even=x^even
so it will be Odd?
Like what he says even thought i was going to say
yes
How do you know when its neither ?
when you plug in -x you get neither f(x) or -f(x) back.
huh?
definitions if f(-x)=f(x) then f is even if f(-x)=-f(x) then f is odd so if f(-x) gives you neither f(x) or -f(x) then f is neither odd or even
short cut methods for polynomials: if all powers are odd, then the function is odd if all powers are even, then function is even
notice here your -4x^3+7x is polynomial and the powers are 3 and 1 the powers are both odd so f is odd this isn't using definition it is a short cut way
another example -4x^3+5 is neither because the powers are 3 and 0 you have a mixture which means it is neither
another example -4x^2+5 is even because the powers are 2 and 0 both powers are even so the function is even
OHOHOHOHHO you explained it so well :D
that is a short cut method for polynomials though if the teacher ask you to show work you will need to do the definition
also you do not want to forget the definition because it will be useful for non-polynomials
-3x3 + 9x2 - 3 so this it odd?
I could give you a lot of short cuts for other functions but it is just too many to list and so that is why learning the definition is also good
no
you have a mixture so it is neither
you have the powers 3,2, and 0
Wait no neither
@freckles
yes?
so neither?
Ok I guess you didn't read my post above "you have a mixture so it is neither'
the mixture is pertaining to you have both odd and even powers in the poly
so 5x^2-5 is even
right because you have 2 and 0
ok honestly all you have to say if it wrong or right
Thanks freckles :D
are you talking to me @Tennis5518 ?
I think me copying and pasting what I said above was confirmation enough @Tennis5518
and np @jagr2713 how far do you want to go in math?
CALC!!!!!
just asking because we need to work on using the definition if you do go further
oH, yea some stuff i dont know lol
\[f(x)=\frac{x^2+1}{x^3-x}\] for example this is not a polynomial how would you determine if this was even or odd
And yes im talkin about u
umm idk @freckles
ok @Tennis5518 as I said I think copying and pasting what I said above was enough
im gave you a medal cause you deserve it but that to confusing
to the people that doesnt know
anyways.... I don't know what you are talking about... I'm going to input -x in place of x \[f(x)=\frac{x^2+1}{x^3-x} \\ f(-x)=\frac{(-x)^2+1}{(-x)^3-(-x)}=\frac{x^2+1}{-x^3+x}=\frac{x^2+1}{-(x^3-x)}=-\frac{x^2+1}{x^3-x}=-f(x)\] do you see what has happened here ?
like first I input -x I used what I said earlier (-x)^even=x^even and (-x)^odd=-x^odd
like (-x)^2=x^2 and (-x)^3=-x^3
now I see that the tops are already the same after doing this so I played with the bottom to see if it was the same as previous bottom or opposite
Ok whatever you say but im just saying your makeing it complicate it
making*
Oh i get it. Thanks :D
anyways I will stop if you think you are learning too much ? (Doctor Tennis orders :p )
Yea i kinda am haha
k
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