Surprise! I'm actually asking a course related question! Simple problem, maybe it's because I'm tired right now but I don't even know where to start! Help is appreciated!
Identify the set of values for X for which Y will be a real number. \[y=\frac{ 2 }{ x + 7 }\]
We want y to be a real number, so 2/(x+7) has to be rational. What value(s) of x are impossible?
-5? But isn't this asking for a set?
No, -5 would still work. You'd get 2/2, which is definitely real. If you have division, the denominator of the fraction can't be zero (because it will be undefined).
Identify the "set of values" for X for which Y will be a real number. Set, meaning multiple. Values, being plural also meaning multiple. It's not asking for "a value of x" for which y will be a real number. How would I come up with said set?
it is not necessary that for \(\Large\frac{2}{x+7}\) to be real it must have to be rational. well any real number is a number that can be represented on the number like. rational numbers like 2,7,5.. are all real irrational numbers like \(\sqrt{2}\),\(\sqrt{3}\).. are also real (because they can be represented on number line). this might help-> \(\Large\frac{any~real}{any~real}=real\)
but remember that indeterminate form like \(\Large \frac{some~number}{0}\) is not considered to be real
Ah, gotcha.
So, for example, same directions but different question: \[y=\sqrt{x+11}\]
I would assume any positive?
Bad grammar I apologize. I would assume, Any positive?*
yes in this question the thing inside the square root cannot be negative so \((x+11)\) must be positive
Thanks for your help! I think I was just confused as to the wording of the question. God Bless! ~SnuggieLad
Lol np :D
Now, where did I put my pencil? ;) I hate it when that happens.
yeah happens ;) normally find it kept inside some book eh xd i got an exam in 20min gtg :D
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