Mathematics
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OpenStudy (pulsified333):
Use the graph of y=f(x) in the accompanying figure to estimate the value of f′(1).
Estimate of f′(1):
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OpenStudy (pulsified333):
OpenStudy (pulsified333):
@dan815 @ganeshie8
OpenStudy (anonymous):
so to find the first derivative, you find the gradient of the tangent drawn at the point x=1
OpenStudy (anonymous):
remember gradient = (y1-y2)/(x1-x2), where (x1,y1) and (x2, y2) are arbitrary points on the tangent.
OpenStudy (pulsified333):
what do you mean arbitrary
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OpenStudy (pulsified333):
@physo
OpenStudy (pulsified333):
@dan815
OpenStudy (anonymous):
i mean take any 2 points on the line
OpenStudy (pulsified333):
which line the curve or red line
OpenStudy (anonymous):
read off two points from the red line and find the gradient by plugging into the above formula
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OpenStudy (pulsified333):
ok
OpenStudy (anonymous):
because red line is a tangent to the curve at the point x=1, which is what we need
OpenStudy (pulsified333):
lets do (2,6) and (1,2)
OpenStudy (pulsified333):
slope = 4
OpenStudy (anonymous):
how exactly did you get 4?
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OpenStudy (pulsified333):
slope formula
OpenStudy (anonymous):
do you understand why the formula works?
OpenStudy (pulsified333):
yeah because its the slope of the line that is also equal to the curve gradient
OpenStudy (anonymous):
its correct, im just making sure you understood what you did
OpenStudy (pulsified333):
okay so is that all i need to do?
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OpenStudy (anonymous):
yes
OpenStudy (pulsified333):
that was correct :D