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Mathematics 18 Online
OpenStudy (pulsified333):

Use the graph of y=f(x) in the accompanying figure to estimate the value of f′(1). Estimate of f′(1):

OpenStudy (pulsified333):

OpenStudy (pulsified333):

@dan815 @ganeshie8

OpenStudy (anonymous):

so to find the first derivative, you find the gradient of the tangent drawn at the point x=1

OpenStudy (anonymous):

remember gradient = (y1-y2)/(x1-x2), where (x1,y1) and (x2, y2) are arbitrary points on the tangent.

OpenStudy (pulsified333):

what do you mean arbitrary

OpenStudy (pulsified333):

@physo

OpenStudy (pulsified333):

@dan815

OpenStudy (anonymous):

i mean take any 2 points on the line

OpenStudy (pulsified333):

which line the curve or red line

OpenStudy (anonymous):

read off two points from the red line and find the gradient by plugging into the above formula

OpenStudy (pulsified333):

ok

OpenStudy (anonymous):

because red line is a tangent to the curve at the point x=1, which is what we need

OpenStudy (pulsified333):

lets do (2,6) and (1,2)

OpenStudy (pulsified333):

slope = 4

OpenStudy (anonymous):

how exactly did you get 4?

OpenStudy (pulsified333):

slope formula

OpenStudy (anonymous):

do you understand why the formula works?

OpenStudy (pulsified333):

yeah because its the slope of the line that is also equal to the curve gradient

OpenStudy (anonymous):

its correct, im just making sure you understood what you did

OpenStudy (pulsified333):

okay so is that all i need to do?

OpenStudy (anonymous):

yes

OpenStudy (pulsified333):

that was correct :D

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