Question

How to solve this problem.

y′=(cos^2x)(cos^2 2y)

Answer 1

separate the variables and integrate

Answer 2

\[\frac{ dy }{ dx }=\cos^2x*\cos^22y\]

Answer 3

\[\frac{ 1 }{ \cos^22y }dy = \cos^2x dx\]

Answer 4

\[\int\limits_{}^{}\frac{ 1 }{ \cos^22y }dy = \int\limits_{}^{}\cos^2x dx\]

Answer 5

@huangtina did u understand?

Answer 6

did u get the answer?

Answer 7

I cannot continue is it right?

Answer 8

your 3rd step from start is wrong.. when u take cos^2 2y to the other side it becomes the reciprocal as wriiten abv..

Answer 9

\[\int\limits_{}^{} \sec^2 (2y) dy = \int\limits_{}^{} \cos^2 x dx\]

Answer 10

got it?

Answer 11

Thank you for helping!

Answer 12

welcome!