Question

what is not a restriction of the product of

Answer 1

\[\frac{5x^2-10x-15 }{x^2-9} \div\frac{ 6x+12 }{ x+2 }\]

Answer 2

Options:
x ≠ -2
x ≠ 9
x ≠ 3
x ≠ -3

Answer 3

I chose x ≠ -2

Answer 4

Can someone let me know if I'm right or not?

Answer 5

Or walk me through the steps or something, just need some help :)

Answer 6

i'm thinking that x ≠ -2 IS a restriction because if you substitute -2 for x in the divisor, then (6x + 12)/(x+2) becomes 0/0 which is disallowed.

I think we need to work the problem and see what happens.

Answer 7

Alright, where should we start from?

Answer 8

Do you know the "wolf" at wolframalpha.com ?

The wolf did the division and came up with this quotient.

http://tinyurl.com/jv8o6wt

Click on the link and follow the division.

Answer 9

Here is the quotient from the "Wolf"

Answer 10

Look at the denominator:

(6x + 12)*(x^2-9)

Solve (6x + 12) for x. @Everly

Also, solve (x^2-9) for x.

These 3 values will be the restricted values.

Then, you can choose the option that is NOT a restricted value from the list of options.

Answer 11

Solve (6x + 12) for x.

Post what you get, okay.

Answer 12

Oh! alright, do I distribute?

Answer 13

Sorry, I left off this:

Solve (6x + 12) = 0 for x.

6x + 12 = 0

Subtract 12 from both sides. No need to distribute.

Answer 14

x = 2 ?

Answer 15

Try again. There is a sign error.

Answer 16

Oh sorry -2 !!

Answer 17

Okay. -2 is restricted.

Two other numbers are restricted.
Find them by solving this second equation for x.

x^2 - 9 = 0

Answer 18

x^2 = 9
x could be ? or x could be ?

Answer 19

@Everly

Answer 20

x could be 3 or -3 ?

Answer 21

Correct.

Restricted values are these three: -2, -3, 3

Look at the options.

Which option is not restricted?

Answer 22

Oh, x ≠ 9 is not restricted ) wow thanks a lot ! To find more i'd just follow those same steps?

Answer 23

x ≠ 9 is what I got, too.

Yes, pretty much. The big deal is not to allow a value of x that creates a result of 0 in a denominator.

Answer 24

If you have another problem like this, we can work on it if you like.

Close this thread and post the problem in a new one.

Your choice.

Answer 25

Yes please! I'll make a new one now