Given a polynomial f(x), if (x + 3) is a factor, what else must be true?
f(3) = 0
f(-3) = 0
f(0) = 3
f(0) = -3
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OpenStudy (anonymous):
@Directrix ?
OpenStudy (anonymous):
Would I be setting the equation to 0?
OpenStudy (jiteshmeghwal9):
By remainder theorem\[f(x)=q(x)(x+3)\]If u put x=-3\[f(-3)=q(-3)(-3+3)\]
Directrix (directrix):
>>Would I be setting the equation to 0? Yes
If (x + 3) is a factor, then x = -3
Directrix (directrix):
If (x + 3) is a factor and x = -3, then then x = -3 is a zero of the function.
It is also an x-intercept and has coordinates (-3,0).
@Everly Which option do you think is correct?
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OpenStudy (anonymous):
Thank you that makes sense and f(0) = -3 seems to make sense to me
Directrix (directrix):
>> f(0) = -3
means that if x = 0, then y = -3.
Directrix (directrix):
We want to get this point: (-3,0).
Directrix (directrix):
x = -3, y = 0
OpenStudy (anonymous):
Oh f(-3) = 0 ?
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Directrix (directrix):
Yes.
OpenStudy (anonymous):
Great! and it makes sense to me too, thank you so much!
OpenStudy (jiteshmeghwal9):
u must know that if (x+a) is a factor of f(x) then
x+a=0=>x=-a is a zero of the function.
f(-a)=0