Question

Given the system of the following linear equations:

5x – 3y = 9

5x + 4y = 23

Solve for x and y.

Question 5 options:

(-2, 3)


(-2, -3)


(3, 2)


(3, -2)

Answer 1

Easy

Answer 2

Will Fan and Medal :D

Answer 3

Yes please

Answer 4

A is not correct @The1LoveGuru

Answer 5

Can you explain @tom982 ?

Answer 6

5x - 3y = 9
5x + 4y = 23

okay so first you have to "eliminate" one of the variables so you can easily "eliminate" X since they have the same coeffiecents

BUT they have to have the opposite signs soooo you end up with

5x - 3y = 9
-5x -4y = -23 ( apply the - sign to everything on both sides)

then you can get rid of the x and solve for the y
so you end up with

-7y = -14
y = -14/-7 = +2


THEN you plug back the 2 into the y variable (any ORIGINAL equation is fine)
so you end up solving for X
5x -3(2) = 9
5x - 6 = 9
5x = 9 +6
5x = 15
x = 15/5 = +3

(3,2 ) I meant C sorry!

Answer 7

I meant C Idek why I chose A. SOrry.

Answer 8

\[5x – 3y = 9\]\[5x + 4y = 23\]Rearrange these to have an equal term:\[5x=9+3y\]\[5x=23-4y\]Equate them:\[9+3y=23-4y\]Simplify\[7y=14\]\[y=2\]Use one of the initial equations and our value for \(y\) to find \(x\):\[5x-3y=9\]\[5x-3(2)=9\]\[5x=15\]\[x=3\]
Giving our solution: \((3,2)\)

Answer 9

That makes a lot of sense and it's OK i haven't submitted it yet :)

Answer 10

I am so sorry dude.

Answer 11

I feel so bad right now.