Two opposite sides of a square with length x are increased by 3 units each and the other two opposite sides are decreased by 3 units each. If the area of the resulting rectangle is 27 unit2, what would be the width of the rectangle?
Hint: area of rectangle = length × width

a)3
b)6
c)9
d)-3
e)-6

Question

Two opposite sides of a square with length x are increased by 3 units each and the other two opposite sides are decreased by 3 units each. If the area of the resulting rectangle is 27 unit2, what would be the width of the rectangle? 
Hint: area of rectangle = length × width


a)3
b)6
c)9
d)-3
e)-6

welshfella · Answer

New length = x + 3' and new width = x - 3
So the area of the rectangle
Is (x+ 3)(x - 3)  = 27

welshfella · Answer

Can you solve this for x?

roxy_martinez · Answer

but which of the answers is the correct then?
a)3
b)6
c)9
d)-3
e)-6

roxy_martinez · Answer

oh I need to solve the x ?

welshfella · Answer

I  can't tell you that. If you find x this will be the length of the square . the width of rectangle will be x - 3

roxy_martinez · Answer

well a solve x a that give me this 


x=6, -6 


the what? it could be B or E

welshfella · Answer

That's the side of the square which must be 6 (side can't be negative)

roxy_martinez · Answer

ok then the correct answer is B 
thank YOU so much :)

welshfella · Answer

What was done to 6 to make width of the rectangle
No the answer is not 6.@

welshfella · Answer

Read the first sentence of the question.