Will fan and metal
Find relative and extremes values of the function f(x)=x^3-6x^2+9x+1

Question

Will fan and metal
Find relative and extremes values of the function f(x)=x^3-6x^2+9x+1

anonymous · Answer

any choices?

kayders1997 · Answer

No

kayders1997 · Answer

I know you have to find the derivative

anonymous · Answer

@Brill might be able to help

anonymous · Answer

I suppose relative and extreme values in this case means local and global maxes and mins
I'm not entirely sure there is a way to do this other than graphing
I would recommend graphing and finding the mins and maxes

kayders1997 · Answer

Thanks

anonymous · Answer

$$f \prime \left( x \right)=3x^2-12x+9$$
$$f \prime \left( x \right)=0,gives~3x^2-12x+9=0,x^2-4x+3=0$$
$$x^2-3x-x+3=0,x \left( x-3 \right)-1\left( x-3 \right)=0,\left( x-3 \right)\left( x-1 \right)=0,x=1,3$$
$$f \prime \prime \left( x \right)=6x-12$$
when x=1,find f"(x) 
when f"(x)<0,there is relative maxima
if f "(x)>0,there is relative minima.
similarly for x=3
?

kayders1997 · Answer

Okay I'm following most of this