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Mathematics 17 Online
OpenStudy (kittiwitti1):

RATE OF CHANGE Q: http://prntscr.com/a3sklv (Wondering if I can simplify any farther than this?) Process: \[f(t)=\sqrt{2t}\rightarrow t=9,t=9+h\]\[\frac{f(9+h)-f(9)}{9+h-9}=\frac{\sqrt{2(9+h)}-\sqrt{2(9)}}{h}=\frac{\sqrt{18+2h}-\sqrt{18}}{h}\]

OpenStudy (kittiwitti1):

o_o so many people!! Hello everyone :-)

OpenStudy (anonymous):

multiply by \[\frac{ \sqrt{18+2h}+18 }{ \sqrt{18+2h}+18 }~and~simplify\]

OpenStudy (kittiwitti1):

I wrote it down but I'm not sure where to go from here, I'm sorry :-( Should I do FOIL?

OpenStudy (anonymous):

numerator is \[\frac{ \sqrt{18+2h}-18 }{ h } \times \frac{ \sqrt{18+2h} +18}{ \sqrt{18+2h}+18 }=\frac{ \left\{ \left( \sqrt{18+2h} \right)^2-18^2 \right\} }{ h \left( \sqrt{18+2h}+18 \right) }\]

OpenStudy (kittiwitti1):

Ok, I got this: \[\frac{(18+2h)-18(\sqrt{18})}{h(\sqrt{18+2h})-18h}\]

OpenStudy (kittiwitti1):

Oh, did I get the right result? :-(

OpenStudy (kittiwitti1):

because f(9) = sqrt(2•9) right

OpenStudy (anonymous):

i missed square root on 18 multiply by \[\frac{ \sqrt{18+2h}-\sqrt{18} }{ h }\times \frac{ \sqrt{18+2h}+\sqrt{18} }{ \sqrt{18+2h} +\sqrt{18}}=?\]

OpenStudy (kittiwitti1):

Ok, I got \[\frac{(18+2h)-18}{h(\sqrt{18+2h})-\sqrt{18}h}\]

OpenStudy (kittiwitti1):

Oops. that can simplify more:\[\frac{2h}{h(\sqrt{18+2h}-\sqrt{18})}=\frac{2}{\sqrt{18+2h}-\sqrt{18}}\]Is this right?

OpenStudy (kittiwitti1):

@surjithayer ??

OpenStudy (anonymous):

write + sign in the denominator.

OpenStudy (kittiwitti1):

Oh yeah, sorry! Thank you :-) @surjithayer so is it right other than the incorrect sign?

jhonyy9 (jhonyy9):

yes is right but you can rationalizing again the denominator for eliminate the radicals from there - do you know it how ?

OpenStudy (kittiwitti1):

@jhonyy9 yes, well not exactly in this case because of the + sign...

jhonyy9 (jhonyy9):

yes this is indifferent than there is plus or minus you can eliminate the radicals from denominator like will be more acceptably - i think

OpenStudy (kittiwitti1):

Do I just multiply by the conjugate? @jhonyy9

jhonyy9 (jhonyy9):

yes beacuse than will get a^2 -b^2 what will result without radicals in denominator - yes ?

OpenStudy (kittiwitti1):

uh. not exactly sure what you said there, but yes, non-radical denominator?

jhonyy9 (jhonyy9):

so this is what mean rationalize the denominator - or not ?

jhonyy9 (jhonyy9):

np

jhonyy9 (jhonyy9):

do you can ending it now sure easy - yes ?

OpenStudy (kittiwitti1):

I got \[\frac{\sqrt{2(9+h)}-3\sqrt{2}}{h}\] Yes?

jhonyy9 (jhonyy9):

how is this exactly - can you rewrite it please from what you start

jhonyy9 (jhonyy9):

2 ------------------- = sqrt(18+2h) +sqrt18 right ?

OpenStudy (kittiwitti1):

Yes. I multiplied by conjugate then simplified

jhonyy9 (jhonyy9):

multiplied by ( (sqrt18 +2h) -sqrt18 ) - yes ?

OpenStudy (kittiwitti1):

The conjugate is just the numerator but switch the signs, yes?

jhonyy9 (jhonyy9):

2((sqrt(18 +2h) -sqrt18) sqrt(18+2h) -sqrt18 --------------------- = ------------------- 18+2h -18 h you have got this result ?

OpenStudy (kittiwitti1):

Yes

jhonyy9 (jhonyy9):

so than is right sure

jhonyy9 (jhonyy9):

good luck bye

OpenStudy (kittiwitti1):

hmm I am not sure who to give medal to now haha

OpenStudy (kittiwitti1):

nvm, he left

OpenStudy (anonymous):

if you again rationalise you will get h again in the denominator

OpenStudy (kittiwitti1):

Yes o-o

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