RATE OF CHANGE Q: http://prntscr.com/a3sklv (Wondering if I can simplify any farther than this?) Process: \[f(t)=\sqrt{2t}\rightarrow t=9,t=9+h\]\[\frac{f(9+h)-f(9)}{9+h-9}=\frac{\sqrt{2(9+h)}-\sqrt{2(9)}}{h}=\frac{\sqrt{18+2h}-\sqrt{18}}{h}\]
o_o so many people!! Hello everyone :-)
multiply by \[\frac{ \sqrt{18+2h}+18 }{ \sqrt{18+2h}+18 }~and~simplify\]
I wrote it down but I'm not sure where to go from here, I'm sorry :-( Should I do FOIL?
numerator is \[\frac{ \sqrt{18+2h}-18 }{ h } \times \frac{ \sqrt{18+2h} +18}{ \sqrt{18+2h}+18 }=\frac{ \left\{ \left( \sqrt{18+2h} \right)^2-18^2 \right\} }{ h \left( \sqrt{18+2h}+18 \right) }\]
Ok, I got this: \[\frac{(18+2h)-18(\sqrt{18})}{h(\sqrt{18+2h})-18h}\]
Oh, did I get the right result? :-(
because f(9) = sqrt(2•9) right
i missed square root on 18 multiply by \[\frac{ \sqrt{18+2h}-\sqrt{18} }{ h }\times \frac{ \sqrt{18+2h}+\sqrt{18} }{ \sqrt{18+2h} +\sqrt{18}}=?\]
Ok, I got \[\frac{(18+2h)-18}{h(\sqrt{18+2h})-\sqrt{18}h}\]
Oops. that can simplify more:\[\frac{2h}{h(\sqrt{18+2h}-\sqrt{18})}=\frac{2}{\sqrt{18+2h}-\sqrt{18}}\]Is this right?
@surjithayer ??
write + sign in the denominator.
Oh yeah, sorry! Thank you :-) @surjithayer so is it right other than the incorrect sign?
yes is right but you can rationalizing again the denominator for eliminate the radicals from there - do you know it how ?
@jhonyy9 yes, well not exactly in this case because of the + sign...
yes this is indifferent than there is plus or minus you can eliminate the radicals from denominator like will be more acceptably - i think
Do I just multiply by the conjugate? @jhonyy9
yes beacuse than will get a^2 -b^2 what will result without radicals in denominator - yes ?
uh. not exactly sure what you said there, but yes, non-radical denominator?
so this is what mean rationalize the denominator - or not ?
np
do you can ending it now sure easy - yes ?
I got \[\frac{\sqrt{2(9+h)}-3\sqrt{2}}{h}\] Yes?
how is this exactly - can you rewrite it please from what you start
2 ------------------- = sqrt(18+2h) +sqrt18 right ?
Yes. I multiplied by conjugate then simplified
multiplied by ( (sqrt18 +2h) -sqrt18 ) - yes ?
The conjugate is just the numerator but switch the signs, yes?
2((sqrt(18 +2h) -sqrt18) sqrt(18+2h) -sqrt18 --------------------- = ------------------- 18+2h -18 h you have got this result ?
Yes
so than is right sure
good luck bye
hmm I am not sure who to give medal to now haha
nvm, he left
if you again rationalise you will get h again in the denominator
Yes o-o
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