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Mathematics 8 Online
OpenStudy (i_need_help_please):

Please Help on Finding Lengths of Triangle *Will Fan and Medal* Only 1 Question

OpenStudy (i_need_help_please):

OpenStudy (mathmale):

What is that symbol between K and M? It's hard to read.

OpenStudy (i_need_help_please):

I think its an e.. Its just another variable so it doesnt really matter.

OpenStudy (devilchild345):

the length (the longer side of the triangle attached to the right angle) would be 12.

OpenStudy (faiqraees):

okay well then just a couple of equations \[\large\rm c^2+d^2=30^2 \]\[\large\rm 6^2+e^2=d^2 \]\[\large\rm 24^2+e^2=c^2 \]

OpenStudy (faiqraees):

substitue third equation in the first equation and then solve it and the second one simultaneously

OpenStudy (i_need_help_please):

I get what your saying but I'm not sure what to do next. @FaiqRaees

OpenStudy (i_need_help_please):

Variable c,e,or d would be 12? @DevilChild345

OpenStudy (devilchild345):

variable c would be 12

OpenStudy (i_need_help_please):

How do you know?

OpenStudy (devilchild345):

wait are you trying to find the length of side KL or side KM

OpenStudy (faiqraees):

\[\large\rm 24^2+e^2+d^2=30^2 \]\[\large\rm 6^2+e^2=d^2 \] solve them simultaneously.

OpenStudy (devilchild345):

where are you getting 30^2

OpenStudy (faiqraees):

from the first equation

OpenStudy (devilchild345):

i see that but there is no 30 on the triangle

OpenStudy (faiqraees):

yeah but there lies a 24 and 6 on a hypotnuse

OpenStudy (i_need_help_please):

I don't know how to solve it with such little information. Its just confusing me.

OpenStudy (i_need_help_please):

I get how your getting all the equations but idk how to "solve them simultaneously"

OpenStudy (faiqraees):

\[\large\rm 24^2+e^2+e^2+6^2=30^2 \] now okay?

OpenStudy (i_need_help_please):

why are there 2 e's?

OpenStudy (faiqraees):

i substitued third equation into it

OpenStudy (i_need_help_please):

I'm just really lost right now. I don't get how you could find the lengths with only one number.

OpenStudy (faiqraees):

which part do you found confusing the last one?

OpenStudy (i_need_help_please):

its not the equations its me not knowing how to solve them. Can you walk through solving it?

OpenStudy (i_need_help_please):

@FaiqRaees

OpenStudy (faiqraees):

well then I assume you know how I formulated the equations and substituted one into another to get a resultant equation?

OpenStudy (i_need_help_please):

yes

OpenStudy (faiqraees):

\[\large\rm 24^2+e^2+e^2+6^2=30^2\] So you dont know how to calculate the value of e in this equation?

OpenStudy (i_need_help_please):

No, thats what confuses me. I understand the equation and how it got there.

OpenStudy (i_need_help_please):

@FaiqRaees

OpenStudy (faiqraees):

\[\large\rm 24^2+e^2+e^2+6^2=30^2\]\[\large\rm 24^2+2e^2+6^2=30^2\] Agree?

OpenStudy (i_need_help_please):

yes

OpenStudy (faiqraees):

\[\large\rm 2e^2=30^2-24^2-6^2\] Agree

OpenStudy (i_need_help_please):

yes

OpenStudy (i_need_help_please):

@FaiqRaees

OpenStudy (faiqraees):

\[\large\rm 2e^2= 900-576-36\]\[\large\rm 2e^2= 288\]\[\large\rm e^2= 144\]\[\large\rm e= 12\]\[\large\rm 6^2+e^2= d^2 \]\[\large\rm 6^2+12^2= d^2 \]\[\large\rm 180= d^2 \]\[\large\rm \sqrt 180= d \] Now try to work out the value of C

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