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Mathematics 6 Online
OpenStudy (steve816):

Help me with this interesting and challenging question. I need smart people!

OpenStudy (steve816):

Express the following expression as a single base to the exponent.

OpenStudy (steve816):

\[\frac{ 15 }{ 2^{-5}+2^{-6}+2^{-7}+2^{-8}}\]

OpenStudy (steve816):

Please someone... this is an extra credit question that I need help on.

imqwerty (imqwerty):

take \(2^{-4}\) common from denominator and then try to simplify

OpenStudy (steve816):

What the hell does that mean

imqwerty (imqwerty):

i mean like this is ur denominator part-> \(2^{-5}+2^{-6}+2^{-7}+2^{-8}\) you can write it like this- \(2^{-4} \left(2^{-1}+2^{-2}+2^{-3}+2^{-4} \right)\) \(2^{-4} \left(\Large\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)\) now simplify the thing inside the brackets and then put this value of denominator into the original expression and then simplify

OpenStudy (anonymous):

OMG, so the answer is just 1!!

OpenStudy (rational):

\[\frac{ 15 }{ 2^{-5}+2^{-6}+2^{-7}+2^{-8}} = \dfrac{2^8*15}{2^3+2^2+2^1+2^0} = ?\]

OpenStudy (anonymous):

Rational, how is that possible??

OpenStudy (rational):

See anything wrong above ?

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