Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

PLEASE HELP!! Will Fan and Medal!! :)

OpenStudy (anonymous):

The equation of line EF is y = 1 over 2x + 6. Write an equation of a line parallel to line EF in slope-intercept form that contains point (0, −2). y = −2x − 2 y = negative 1 over 2x + 2 y = 1 over 2x − 2 y = − 2x + 2

OpenStudy (anonymous):

can you please explain?

OpenStudy (faiqraees):

\[\large\rm y = \frac{1} {2x}+6 \] is this the equation?

OpenStudy (anonymous):

yes!

OpenStudy (faiqraees):

if thats the case then \[\large\rm y= -2x+c\] clear?

OpenStudy (anonymous):

no sorry :(

OpenStudy (faiqraees):

\[\large\rm m_1m_2=-1\] the m1 is the gradient/slope of first line and m2 is the gradient/slope of second line. \[\large\rm \frac{1}{2x}m_2=-1\]\[\large\rm m_2=-2x\]\[\large\rm y=mx+c\]\[\large\rm y=-2x+c\]

OpenStudy (faiqraees):

now clear?

OpenStudy (anonymous):

I'm trying to understand but what does the c represent?

OpenStudy (faiqraees):

c is just a constant or y intercept

OpenStudy (anonymous):

ok i'm still kind of confused i'm sorry it's really hard for me to understand some things especially math

OpenStudy (anonymous):

what DogzCatz right?

OpenStudy (anonymous):

was oops

OpenStudy (faiqraees):

it's just a constant which will tell how much the line will be above or below x-axis. Remember it's not the answer.

OpenStudy (faiqraees):

no dogcatz wasnt right

OpenStudy (faiqraees):

btw I have to go so I am just going to write the complete solution. \[\large\rm y=-2x+c\]\[\large\rm y=-2, x =0 \]\[\large\rm -2=0+c \]\[\large\rm -2=c \]\[\large\rm y=-2x-2~is~the~equation \]

OpenStudy (anonymous):

I'm still trying to understand but thank you for your explanation!!! :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!