HELP!!
@4everaddicted2anime
whats ur question?
\[f(x)=\frac{ x^2 }{ 16 }=2x\]
sry idk
Its okay thanks for trying
4ever im sorry i didnt reply a bit ago i had to go to lunch
Were you given an x value to plug in? It's okay
What do you have to do?
yeah sorry x=8
A. –15 B. 20 C. –12 D. –24
Okay so first you need to plug in 8 for every x you see. You should get \[f(8)=\frac{ 8^2 }{ 16 }=2(8)\] Now you need to simplify whatever can be simplified. The first part would be 8^2 and 2(8). After doing this you should get\[f(8)=\frac{ 64 }{ 16 }=16\] Next you need to multiply by 16 on both sides to cancel out the denominator. You should get \[f(8)=64=256\] I'm confused. Is this all you were given to solve this?
yes
i have to find the value of f(x)
Ohh. Don't pay any attention to what I said in the last post. All you need to do is plug in the answers to see if they are true. First lets use -15. \[f(-15)=\frac{ (-15)^2 }{ 16 }=2(-15)\] Simplify what can be to get\[f(-15)=\frac{ 225 }{ 16 }=-30\] Now multiply by 16 on both sides of the second = sign to get\[f(-15)=225\neq480\] Since 225 does not equal 480, this answer is not true
okay so we rule out -15
so its b c or d
I'll be back shortly
alrighty
Now lets try using b which is 20. \[f(20)=\frac{ 20^2 }{ 16 }=2(20)\] Simplify the multiplication areas to get\[f(20)=\frac{ 400 }{ 16 }=40\] Multiply by 16 on both sides to get rid of the denominator. You should have got\[f(20)=400\neq640\] This means that option b is not true.
so a and b are out of the question
Now lets try using c which is -12\[f(-12)=\frac{ (-12)^2 }{ 16 }=2(-12)\] Simplify the multiplication areas to get\[f(-12)=\frac{ 144 }{ 16 }=-24\] Multiply by 16 on both sides to get rid of the denominator. You should have got\[f(-12)=144\neq-384\] This means that option c is not true.
So its D!
yes
you deserve 5 medals for spending 30 minutes on it lol
aww thanks
can you help with a few more so i can give more medals?
sure
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