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OpenStudy (isuckatschool43):
OpenStudy (isuckatschool43):
4500 pi in^3?
OpenStudy (michele_laino):
hint:
the requested volume is given by the subsequent formula:
\[\Large V = \frac{{4\pi }}{3}{\left( {\frac{D}{2}} \right)^3}\]
where \(D\) is the diameter
OpenStudy (michele_laino):
I think that your answer is correct!
OpenStudy (isuckatschool43):
ok thank you! do you have time for a few more? @Michele_Laino
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OpenStudy (michele_laino):
ok!
OpenStudy (isuckatschool43):
OpenStudy (isuckatschool43):
C?
OpenStudy (michele_laino):
we can apply the same formula above:
\[\Large V = \frac{{4\pi }}{3}{R^3} \simeq \frac{{4 \times 3.14}}{3} \times {3^3} = ...?\]
OpenStudy (michele_laino):
yes! I confirm option C
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