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Mathematics 15 Online
OpenStudy (isuckatschool43):

pls help i will fan and medal

OpenStudy (isuckatschool43):

OpenStudy (isuckatschool43):

4500 pi in^3?

OpenStudy (michele_laino):

hint: the requested volume is given by the subsequent formula: \[\Large V = \frac{{4\pi }}{3}{\left( {\frac{D}{2}} \right)^3}\] where \(D\) is the diameter

OpenStudy (michele_laino):

I think that your answer is correct!

OpenStudy (isuckatschool43):

ok thank you! do you have time for a few more? @Michele_Laino

OpenStudy (michele_laino):

ok!

OpenStudy (isuckatschool43):

OpenStudy (isuckatschool43):

C?

OpenStudy (michele_laino):

we can apply the same formula above: \[\Large V = \frac{{4\pi }}{3}{R^3} \simeq \frac{{4 \times 3.14}}{3} \times {3^3} = ...?\]

OpenStudy (michele_laino):

yes! I confirm option C

OpenStudy (isuckatschool43):

okay. I have 2 more left

OpenStudy (michele_laino):

that's right! \[\Large V = \frac{{4\pi }}{3}{R^3} \simeq \frac{{4 \times 3.14}}{3} \times {12^3} = ...?\]

OpenStudy (isuckatschool43):

last one!

OpenStudy (michele_laino):

that's right! \[\Large V = \frac{{4\pi }}{3}{R^3} \simeq \frac{{4 \times 3.14}}{3} \times {21^3} = ...?\]

OpenStudy (isuckatschool43):

Thank you so much for helping me! You are a really good explainer!

OpenStudy (michele_laino):

:)

OpenStudy (isuckatschool43):

Bye!

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