The volume of a box(V) varies directly with its length(l). If one of the boxes has a volume of 288 cubic inches and a length of 12 inches, what is the constant of proportionality for the group of boxes?
3,456
24
1/24
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OpenStudy (countrygirl1431):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
I'm going to represent the length as upper case L instead of lower case l
jimthompson5910 (jim_thompson5910):
The volume of a box(V) varies directly with its length(L).
so that means
V = k*L
where k is some fixed number
OpenStudy (countrygirl1431):
ok
jimthompson5910 (jim_thompson5910):
`one of the boxes has a volume of 288 cubic inches and a length of 12 inches`
so...
V = 288
L = 12
plug these values into the equation V = k*L to get...
V = k*L
288 = k*12
now solve for k to get k = ???
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jimthompson5910 (jim_thompson5910):
does that make sense?
OpenStudy (countrygirl1431):
yes
OpenStudy (countrygirl1431):
@jim_thompson5910 would i divide both sides by 12 to get my answer
jimthompson5910 (jim_thompson5910):
yes you would
jimthompson5910 (jim_thompson5910):
to undo the multiplication of 12
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