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Chemistry 13 Online
OpenStudy (anonymous):

A solution contains .530 mol of isopropanol (C3H7OH) dissolved in .870 mol water. ( a ) What is the mole fraction of isopropanol? (b ) What is the mass percent of isopropanol? (c ) What is the molality of isopropanol?

OpenStudy (anonymous):

@Photon336

OpenStudy (anonymous):

@ganeshie8

OpenStudy (priyar):

do u know the formula for mole fraction?

OpenStudy (anonymous):

@priyar no

OpenStudy (priyar):

molefraction of solute = moles of solute/(moles of solute+moles of solvent)

OpenStudy (priyar):

here what is the solute and solvent?

OpenStudy (anonymous):

The solute is isopropanol and the solvent is water.

OpenStudy (priyar):

good so plug in the appropriate values in the abv eq.

OpenStudy (anonymous):

mol frac = .530/(.530+.870)

OpenStudy (priyar):

good!!

OpenStudy (anonymous):

=.37857

OpenStudy (priyar):

good job!

OpenStudy (anonymous):

Is that it for that part?

OpenStudy (priyar):

yup!

OpenStudy (priyar):

what is mass percent?

OpenStudy (anonymous):

not really sure. I know I will need to times by 100

OpenStudy (priyar):

i thought u must have learnt it in ur school..

OpenStudy (priyar):

anyway, mass percent = (mass of solute/mass of solution) * 100

OpenStudy (anonymous):

@priyar Would the solution be water and the isopropanol?

OpenStudy (priyar):

yes together they make the solution

OpenStudy (anonymous):

mass percent = .530/1.4 *100

OpenStudy (anonymous):

=38%

OpenStudy (priyar):

no u have not substituted the mass..

OpenStudy (priyar):

u have substituted the moles..

OpenStudy (anonymous):

So do I need to change the solute and solution to grams?

OpenStudy (priyar):

yes

OpenStudy (anonymous):

31.85 g Iso/109.333g Iso &H2O *100=29.13

OpenStudy (anonymous):

29.13%

OpenStudy (anonymous):

@priyar would it be just 29%?

OpenStudy (priyar):

31.85 g Iso/109.333g Iso &H2O *100=29.13??

OpenStudy (anonymous):

@priyar Is that wrong?

OpenStudy (priyar):

31.8g is correct but what is "Iso" ???

OpenStudy (anonymous):

Oh, I was abbreviating isopropanol

OpenStudy (anonymous):

Is the rest of it correct?

OpenStudy (priyar):

oh ok and for water it is .870 *18 =15.66 to get mass of solution add both masses

OpenStudy (priyar):

@Photon336 they've asked for "molality"

OpenStudy (photon336):

i see then that's mol of solute per kilogram of solution

OpenStudy (priyar):

@staldk3 what do u get as the mass of solution?

OpenStudy (anonymous):

Wait what about the water?

OpenStudy (priyar):

mass of water =15.66g

OpenStudy (priyar):

now tell me the mass of the entire solution..

OpenStudy (anonymous):

15.66g+31.8g = 47.46g

OpenStudy (priyar):

good! so what will be the mass percent?

OpenStudy (anonymous):

67.00%

OpenStudy (priyar):

great!

OpenStudy (priyar):

now u must be knowing molality formula right?

OpenStudy (priyar):

@staldk3

OpenStudy (anonymous):

m= moles solute/kg solvent

OpenStudy (priyar):

good! now plug in the appropriate values!

OpenStudy (anonymous):

31.8g/.01566kg

OpenStudy (priyar):

great! simplify

OpenStudy (anonymous):

I got a crazy number

OpenStudy (anonymous):

2030.65

OpenStudy (priyar):

yes correct.

OpenStudy (priyar):

did u understand ?

OpenStudy (anonymous):

@priyar Sorry. I had internet issues.

OpenStudy (anonymous):

@priyar It counted it wrong when I put 2030 for sig figs

OpenStudy (priyar):

its ok! was the answer to the 3rd part wrong?

OpenStudy (priyar):

@staldk3 ?

OpenStudy (anonymous):

Yes. Sorry. Went to do something since no one was on.

OpenStudy (priyar):

np. but what did u say abt significant fig.

OpenStudy (anonymous):

Shouldn't it be only 3 sig figs? So 2030?

OpenStudy (priyar):

are they asking for sig fig in the Q?

OpenStudy (anonymous):

They usually want sig figs. Is 3 sig figs not right?

OpenStudy (priyar):

2030.65 this has 6 sig fig

OpenStudy (anonymous):

Right but when you're doing problems you're suppose to take the least amount of sig figs as what the problem/equation contains right?

OpenStudy (priyar):

hey sry.. i don't know how i failed to notice the mistake when u wrote 31.8/0.01566... no of moles os solute should be the numerator..not mass..

OpenStudy (priyar):

u wrote the formula correctly..but plugged in the wrong value....

OpenStudy (priyar):

number of moles of solute should be the numerator..not mass..

OpenStudy (anonymous):

So I should flip it?

OpenStudy (priyar):

why?no

OpenStudy (priyar):

can u write the formula again?

OpenStudy (anonymous):

m= moles solute/kg solvent

OpenStudy (anonymous):

Sorry had to find it.

OpenStudy (priyar):

u must remember these formulae always..coz u use them a lot ... now plug in the correct values..

OpenStudy (anonymous):

.530/.01566

OpenStudy (anonymous):

=33.84

OpenStudy (priyar):

correct!

OpenStudy (anonymous):

So would it be 33.8 for sig figs?

OpenStudy (priyar):

no..the least is 2 sig. fig

OpenStudy (anonymous):

So 34

OpenStudy (priyar):

Perfect!

OpenStudy (priyar):

good job!

OpenStudy (anonymous):

Thanks and thanks for the help!

OpenStudy (priyar):

U r welcome!

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