A solution contains .530 mol of isopropanol (C3H7OH) dissolved in .870 mol water.
( a ) What is the mole fraction of isopropanol?
(b ) What is the mass percent of isopropanol?
(c ) What is the molality of isopropanol?
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OpenStudy (anonymous):
@Photon336
OpenStudy (anonymous):
@ganeshie8
OpenStudy (priyar):
do u know the formula for mole fraction?
OpenStudy (anonymous):
@priyar no
OpenStudy (priyar):
molefraction of solute = moles of solute/(moles of solute+moles of solvent)
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OpenStudy (priyar):
here what is the solute and solvent?
OpenStudy (anonymous):
The solute is isopropanol and the solvent is water.
OpenStudy (priyar):
good so plug in the appropriate values in the abv eq.
OpenStudy (anonymous):
mol frac = .530/(.530+.870)
OpenStudy (priyar):
good!!
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OpenStudy (anonymous):
=.37857
OpenStudy (priyar):
good job!
OpenStudy (anonymous):
Is that it for that part?
OpenStudy (priyar):
yup!
OpenStudy (priyar):
what is mass percent?
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OpenStudy (anonymous):
not really sure. I know I will need to times by 100
OpenStudy (priyar):
i thought u must have learnt it in ur school..
OpenStudy (priyar):
anyway, mass percent = (mass of solute/mass of solution) * 100
OpenStudy (anonymous):
@priyar Would the solution be water and the isopropanol?
OpenStudy (priyar):
yes together they make the solution
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OpenStudy (anonymous):
mass percent = .530/1.4 *100
OpenStudy (anonymous):
=38%
OpenStudy (priyar):
no u have not substituted the mass..
OpenStudy (priyar):
u have substituted the moles..
OpenStudy (anonymous):
So do I need to change the solute and solution to grams?
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OpenStudy (priyar):
yes
OpenStudy (anonymous):
31.85 g Iso/109.333g Iso &H2O *100=29.13
OpenStudy (anonymous):
29.13%
OpenStudy (anonymous):
@priyar would it be just 29%?
OpenStudy (priyar):
31.85 g Iso/109.333g Iso &H2O *100=29.13??
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OpenStudy (anonymous):
@priyar Is that wrong?
OpenStudy (priyar):
31.8g is correct but what is "Iso" ???
OpenStudy (anonymous):
Oh, I was abbreviating isopropanol
OpenStudy (anonymous):
Is the rest of it correct?
OpenStudy (priyar):
oh ok and for water it is .870 *18 =15.66 to get mass of solution add both masses
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OpenStudy (priyar):
@Photon336 they've asked for "molality"
OpenStudy (photon336):
i see then that's mol of solute per kilogram of solution
OpenStudy (priyar):
@staldk3 what do u get as the mass of solution?
OpenStudy (anonymous):
Wait what about the water?
OpenStudy (priyar):
mass of water =15.66g
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OpenStudy (priyar):
now tell me the mass of the entire solution..
OpenStudy (anonymous):
15.66g+31.8g = 47.46g
OpenStudy (priyar):
good! so what will be the mass percent?
OpenStudy (anonymous):
67.00%
OpenStudy (priyar):
great!
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OpenStudy (priyar):
now u must be knowing molality formula right?
OpenStudy (priyar):
@staldk3
OpenStudy (anonymous):
m= moles solute/kg solvent
OpenStudy (priyar):
good! now plug in the appropriate values!
OpenStudy (anonymous):
31.8g/.01566kg
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OpenStudy (priyar):
great! simplify
OpenStudy (anonymous):
I got a crazy number
OpenStudy (anonymous):
2030.65
OpenStudy (priyar):
yes correct.
OpenStudy (priyar):
did u understand ?
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OpenStudy (anonymous):
@priyar Sorry. I had internet issues.
OpenStudy (anonymous):
@priyar It counted it wrong when I put 2030 for sig figs
OpenStudy (priyar):
its ok! was the answer to the 3rd part wrong?
OpenStudy (priyar):
@staldk3 ?
OpenStudy (anonymous):
Yes. Sorry. Went to do something since no one was on.
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OpenStudy (priyar):
np. but what did u say abt significant fig.
OpenStudy (anonymous):
Shouldn't it be only 3 sig figs? So 2030?
OpenStudy (priyar):
are they asking for sig fig in the Q?
OpenStudy (anonymous):
They usually want sig figs. Is 3 sig figs not right?
OpenStudy (priyar):
2030.65 this has 6 sig fig
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OpenStudy (anonymous):
Right but when you're doing problems you're suppose to take the least amount of sig figs as what the problem/equation contains right?
OpenStudy (priyar):
hey sry.. i don't know how i failed to notice the mistake when u wrote 31.8/0.01566... no of moles os solute should be the numerator..not mass..
OpenStudy (priyar):
u wrote the formula correctly..but plugged in the wrong value....
OpenStudy (priyar):
number of moles of solute should be the numerator..not mass..
OpenStudy (anonymous):
So I should flip it?
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OpenStudy (priyar):
why?no
OpenStudy (priyar):
can u write the formula again?
OpenStudy (anonymous):
m= moles solute/kg solvent
OpenStudy (anonymous):
Sorry had to find it.
OpenStudy (priyar):
u must remember these formulae always..coz u use them a lot ... now plug in the correct values..
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OpenStudy (anonymous):
.530/.01566
OpenStudy (anonymous):
=33.84
OpenStudy (priyar):
correct!
OpenStudy (anonymous):
So would it be 33.8 for sig figs?
OpenStudy (priyar):
no..the least is 2 sig. fig
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