The wavelengths involved in the spectrum of deuterium are slightly different from that of hydrogen spectrum because- 1).Size of two nuclei are different 2).Nuclear forces are different in two cases 3).Masses of two nuclei are different 4).Attraction between the electron and the nucleus is different ...
@priyar plss..help
@Michele_laino sir pls help
@Vincent-Lyon.Fr sir pls help
i think option C is correct !
because ENERGY DIFFERENCE is dependent on MASS OF NUCLEI.
Can u plss give the relation?
N energy difference between two energy states is given by Rz^2(1/n1^2-1/n2^2) in case of hydrogen like species spectrum....
R depends on MASS
Sure...???
Lemme check then....
sure
Value of R comes out to be 2mπ^2k^2e^4/h^2
i don't remember the exact value but i knew it depends on mass as you can see
Well , thanks @mayankdevnani it's correct the expression that i gave n the ans u proposed....
alright ! Thumbs Up :)
I think it is since the masses of the two nuclei are different. The problem in writing the energy leves of a system of a hydrogen like atom is a two-body problem, so it involves the consideration of the reduced \(\mu\) mass of such system: \[\huge \frac{1}{\mu } = \frac{1}{{{m_e}}} + \frac{1}{M}\] where \(m_e\) is the mass of the electron, and \(M\) is the mass of the nucleus of such hydrogen-like atom
of course, the reduced mass changes, when we change the hydrogen-like atom type
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