Question

what is the density of a metal spoon of weight 0.48N in air & its weight in water is 0.42N

Answer 1

\[D=w1\div (w1-w2)*1000 kg/m^3 \]
where D= density of metal spoon, w1=0.48N, w2=0.42N.
So, by putting these values, we get-
\[D=8000 kg/m^3\]

Answer 2

thanks so much!