Find the following and show all work including the trigonometric ratios used: The measure of angle A The length of side AB The length of side BC
@563blackghost I think I can do this but I might need help again, sorry!
Alrighty....well i'll let you know which equations to use and see if you can input and solve ok?
Okay
Well to find the length of AB you would use \[\sin (\angle x)=\frac{ opposite }{ hypotenuse }\]
Hint: The hypotenuse in the equation would be x...
Hmm I know so far the we will use 30, but where does 20 come in? isn't it adjacent?
20 is the angle so we would input it where sin is....\[\sin (20)\]
So would I get the sin of 20 then multiply it by 30?
Since the equation has 30 over x we would actually divide.... \(\LARGE\color{red}{30/\sin (20)}\)
I got 87.71
Correct ^^
Now we would solve the adjacent angle...Now you know the opposite and want to know the adjacent angle so we would use tan.... \[\tan(20)=\frac{ opposite }{ adjacent }\]
adjacent side* not angle
Ok so the same as before but with tan?
Yup ^^
I got 82.42
Correct again ^^
Now to find angle A its not that hard ^^ First determine what the two degree of a triangle is....next you would analyze the triangle I see a right angle which means 90 degrees and I know one angle is 20 degrees so you would simply add 90 and 20 and then subtract it from the total degree of a triangle....
total* not two
70, right? Since right angles equal 180 degrees
Yes it is 70 but because the total degree of a triangle is 180 ^^ So angle A is \(\Large{70^{o}}\)
ohh ok
And we answered all ^^ and if you need to put 82 or 87 in radical form its impossible...
Awesome! Thank you so much, I really appreciate it :D
Np ^^
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