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Mathematics 13 Online
OpenStudy (anonymous):

I know this is a Chemistry question but there aren't helpers there so... I figured everything else out but I just need help on the last step that I am doing: M(HBr) = 0.50 moles / 0.030 L = M To further explain what I'm asking, I need help calculating the concentration of HBr. Formula - M=n/V n = 0.50 mol V = 0.030 L So as listed above, the set up of the formula would be: M(HBr) = 0.50 moles / 0.030 L = M And I need help finding M

OpenStudy (baconboy73):

You're perfectly on track, all you have to do now is punch in the numbers. \[\frac{ 0.50mol }{ 0.030L }=16.6666M = 17M\] 17 because of significant figures.

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

That's what I got too, but a lot of the examples my school gave us was around "0.0(additional two digits here)." For example: M(HCl) = 0.003 moles ÷ 0.025 L = 0.12 moles/L or 0.12M

OpenStudy (anonymous):

So when I got 16.6666/17, I thought it was just way too high.

OpenStudy (baconboy73):

Interesting. Yeah, your example should only have 1 sigfig. And yes, concentrations of 17M are hardly found, at least that's what I've had throughout my Chem learning. It's always tiny, like 0.00000123...

OpenStudy (anonymous):

Yeah, well thank you so much for your help! If it's wrong, it's probably from what I did in the earlier steps lol. I hate doing Titrations lol

OpenStudy (baconboy73):

I'd better warn you then... if you keep going into higher chem you'll be doing titrations regularly ;P

OpenStudy (anonymous):

Oh man lol. Would it be too much to ask you to check my work? I have everything filled out, but just would like an extra set of eyes on it, if you don't mind.

OpenStudy (baconboy73):

Go ahead.

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