Question

Quesstion

Answer 1

its blurry

Answer 2

http://assets.openstudy.com/updates/attachments/56c4c109e4b004c3c3905e44-mathmath333-1455735966506-untitle57575d.png

Answer 3

hmm....looks hard :/

Answer 4

@AlexandervonHumboldt2 @Astrophysics @dan815 a little help pls?

Answer 5

\[a+b+c=80\] is one equation

Answer 6

\[\frac{a-8,000}{b-12,000}=\frac{2}{3}\] is another
so is \[\frac{b-12,000}{c-15,000}=\frac{3}{4}\] and finally \[\frac{a-8000}{c-15,000}=\frac{1}{2}\]

Answer 7

4b-48000=3c-45000
4b=3c-45000+48000
4b=3 c +3000
\[b=\frac{ 3 }{ 4 }c+750\]
2a-16000=c-15000
2a=c-15000+16000
2a=c+1000
\[a=\frac{ 1 }{ 2 }c+500 \]
a+b+c=80,000
\[\frac{ 1 }{ 2 }c+500+\frac{ 3 }{ 4 }c+750+c=80,000\]
multiply by 4
2c+2,000+3c+3000+4c=3,20,000
9c=3,20,000-5,000=3,15,000
c=35,000
\[a=\frac{ c }{ 2 }+500=\frac{ 35,000 }{ 2 }+500=17,500+500=18,000\]
\[b=\frac{ 3 }{ 4 }c+750=\frac{ 3 }{ 4 }\times 35,000+750=26,250+750=27,000 \]
now find the savings of each

Answer 8

we don't need savings so a,b,c are the reqd. incomes.