Question

The domain of the function y(x) =3 cos(5x-4) +1 is all real numbers. Which of the following is the range of the function y(x) ?

Answer 1

Here are the answer choices

\[a. -3\le y(x) \le 3\] \[b. -4\le y(x) \le 3\] \[c. -4 \le y(x) \le 2\] \[d. -2 \le y(x) \le 4\]

Answer 2

The answer is D but I need an explanation..

Answer 3

@mathstudent55 @zepdrix @dan815 @Redcan @tom982 @whpalmer4 @inkyvoyd @pooja195

Answer 4

you just need to keep in mind that cosx takes value form -1 to 1

Answer 5

so for least value it is -1 and if you insert you get : 3*(-1)+1=-2 for the maximum it is 1 and you have 3*1+1=4 so [-2;4]

Answer 6

@sparrow2 how did u know that it was cosx? Sorry I new to this kind of material

Answer 7

from your equation it is cos(5x-4) it...argument doesn't matter the range of cosx is [-1,1]

Answer 8

cos(t) will be, at most 1 and at least -1

3 * (-1) + 1 = -3 + 1 = -2
3 * (1) + 1 = 3 + 1 = 4

So the range is [-2 , 4]

Answer 9

Thanks for the clarification!

Answer 10

np =] medal + fan me thankz