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OpenStudy (hybrik):
log 2^25 + log 4^5 my bad
OpenStudy (jdoe0001):
\(\large log_225+log_45?\)
jhonyy9 (jhonyy9):
do you know the property of logarithm ?
jhonyy9 (jhonyy9):
log a^x = xlog a
for example
jhonyy9 (jhonyy9):
or
log a + log b = log (a*b)
do you know these ?
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jhonyy9 (jhonyy9):
without them you not can solving exercises like this never
jhonyy9 (jhonyy9):
@hybrik what is your opinion please ?
OpenStudy (kayders1997):
Hi
OpenStudy (hybrik):
@jhonyy9 Sorry I had to shower, Im good at math but my weakness is logarithims, I do know it
jhonyy9 (jhonyy9):
ok. so how can i help you ?
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OpenStudy (hybrik):
just dont know how to simplify
jhonyy9 (jhonyy9):
check please the above wrote property and try getting from there what formula you can us here ? wait
jhonyy9 (jhonyy9):
but sorry first in the left term there is 2 like base and in the right term there is 4 like base term so how can you make the 4 to be same with 2 using exponent ?
jhonyy9 (jhonyy9):
log 2^25 + log 4^5 =
4= 2^2 yes ?
OpenStudy (hybrik):
yea
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jhonyy9 (jhonyy9):
so 4^5 = (2^2)^5 = ?
OpenStudy (hybrik):
yea
jhonyy9 (jhonyy9):
= 2^?
OpenStudy (hybrik):
2log2^5?
jhonyy9 (jhonyy9):
first without log please answer this question
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OpenStudy (hybrik):
= 2^? one?
jhonyy9 (jhonyy9):
yes what number will get in place of ?
OpenStudy (hybrik):
idk what your asking
OpenStudy (hybrik):
2^? = 2^x?
jhonyy9 (jhonyy9):
(x^a)^b = x^(?)
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jhonyy9 (jhonyy9):
property of exponents
OpenStudy (hybrik):
idk
OpenStudy (hybrik):
a x^b?
jhonyy9 (jhonyy9):
why ? you have said me that you dont know the logarithm and now you say that you dont know the property of exponents - so when wan you learning them ?
OpenStudy (hybrik):
idk im in 6th grade
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OpenStudy (hybrik):
i teach myself, logx2b = xlogxb?
jhonyy9 (jhonyy9):
but you have learned about exponents - yes ?
OpenStudy (hybrik):
yea
jhonyy9 (jhonyy9):
sorry but this logx2b i dont understand how you have wrote there
OpenStudy (hybrik):
just continue ur x2ab thing
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jhonyy9 (jhonyy9):
so when there are exponent on exponent so the exponents are coming multiplied
(x^a)^b = x^(a*b)
ok. ? remember and learn it please
OpenStudy (hybrik):
oh yea i know that
OpenStudy (hybrik):
misread it my bad
jhonyy9 (jhonyy9):
now this is easy to say that i know
sorry
jhonyy9 (jhonyy9):
so how you can continue it your exercise ?
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OpenStudy (hybrik):
idk
jhonyy9 (jhonyy9):
what you have got ? in the last step ?
OpenStudy (hybrik):
2log2^5
OpenStudy (hybrik):
cause log4 ^ 5 = log 2^2 ^5
OpenStudy (hybrik):
and you can move the 2 to have 2log2 ^ 5
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jhonyy9 (jhonyy9):
log 2^25 + log 4^5 =
no
first i have said that without logarithm
4^5 = 2^(?)
OpenStudy (hybrik):
4^5 = 2^2^5
OpenStudy (hybrik):
(2^2)^5
jhonyy9 (jhonyy9):
2^(?)
jhonyy9 (jhonyy9):
because in the first term there is 2 on exponent so you need using in the second 2 on exponent - do you understand it now why ?
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jhonyy9 (jhonyy9):
2^2^5 = 2^(2*5) =?
OpenStudy (hybrik):
yea
OpenStudy (hybrik):
wait no
OpenStudy (hybrik):
wait yes
jhonyy9 (jhonyy9):
please write what i ask you
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jhonyy9 (jhonyy9):
2^(2*5) = ?
OpenStudy (hybrik):
oh i didnt see that message sorry
OpenStudy (hybrik):
1024
jhonyy9 (jhonyy9):
nonono
jhonyy9 (jhonyy9):
the base need being 2
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OpenStudy (hybrik):
it is already 2^10?
jhonyy9 (jhonyy9):
exactly
jhonyy9 (jhonyy9):
log 2^25 +log 2^10 = log ?
than you know this formula log a +log b = log a*b
OpenStudy (hybrik):
yeah
OpenStudy (hybrik):
uhm = log 2 250
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OpenStudy (hybrik):
where log 2 ^10 come from
OpenStudy (hybrik):
did u move the 2 on the 5, wouldnt you move it to be 2log2^5 and not log2^10?
jhonyy9 (jhonyy9):
check above 4^5 = 2^2^5 = 2^(2*5) = 2^10
yes ?
OpenStudy (hybrik):
yes
jhonyy9 (jhonyy9):
because in the first term there is 2^25 - yes ?
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jhonyy9 (jhonyy9):
so please
log 2^25 +log 2^10 = log ?
use the above wrote formula please
OpenStudy (hybrik):
wait r u simplifying log 4^5 or log 2^25?
OpenStudy (hybrik):
@jhonyy9 i said log 2 250
jhonyy9 (jhonyy9):
why ?
how you know a^x *a^y = ?
OpenStudy (hybrik):
u multiply the exponents when adding, so log 25*10 = log 2 250?
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jhonyy9 (jhonyy9):
no
multiplie the exponents just when there are exponents on exponents
jhonyy9 (jhonyy9):
in this case of multiplie the same terms with exponents just assum the exponents
property of exponents - sorry what you need learning again i see
jhonyy9 (jhonyy9):
so how will be ?
jhonyy9 (jhonyy9):
2^25 *2^10 = 2^?
jhonyy9 (jhonyy9):
please cooperate because i need to go
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jhonyy9 (jhonyy9):
where are you from please ? because here in Europe is in the night 3,12
jhonyy9 (jhonyy9):
are you here ?
OpenStudy (hybrik):
was eating sorry?
OpenStudy (hybrik):
@jhonyy9 2^35
jhonyy9 (jhonyy9):
ok
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jhonyy9 (jhonyy9):
so now there you have got log 2^35 = ?
using this formula log a^x = xlog a
OpenStudy (hybrik):
35 log2?
jhonyy9 (jhonyy9):
35log 2 hence please
because than you write 35 log2
so this mean 35 space log base 2 of nothing
OpenStudy (hybrik):
ok, its not an answer choice so its wrong?
OpenStudy (hybrik):
r u sure u can just do 2log2^5 + log2^25
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