I'm not sure how to do this, please don't just give the answer and show me how to do it step by step.
Divide (9x^4y^3 + 3x^3y^2 - 6x^2y - 12x^2y^4) by -3x^2y

Question

I'm not sure how to do this, please don't just give the answer and show me how to do it step by step.
Divide (9x^4y^3 + 3x^3y^2 - 6x^2y - 12x^2y^4) by -3x^2y

phi · Answer

term by term

anonymous · Answer

hey can you use equation editor and right this one again.

anonymous · Answer

Yes, of course, sorry.

anonymous · Answer

$$\frac{9x^4y^3}{-3x^2y}=?$$

anonymous · Answer

Divide $$(9x^4y^3 + 3x^3y^2 - 6x^2y - 12x^2y^4) $$ by $$ -3x^2y$$

anonymous · Answer

Also @phi what do you mean "term by term"?

anonymous · Answer

like what i wrote, that is the first term

anonymous · Answer

Oh! Ah, sorry, I must have missed that when I was rewriting for newtonson. 
How would I be able to find the answer for the term? I haven't done this in a while, I don't remember much.

rhondasommer · Answer

Welcome to Openstudy; Becayse Satellite73 helped you so much; a natrual thing to do is to hit the "Best Response" button. It is a sort of reward for those who help you :)

anonymous · Answer

I didn't really get any help though?? I was just told term by term and given an equation, I still have absolutely no clue what I'm supposed to be doing.

rhondasommer · Answer

ah; then I shall help you

anonymous · Answer

Thank you. I would appreciate that.

rhondasommer · Answer

:)

rhondasommer · Answer

$$ (9x^4y^3 + 3x^3y^2 - 6x^2y - 12x^2y^4) /(-3x^2y)$$

rhondasommer · Answer

you can simplify the x and y's by dividing$$x^2y$$. $$9x^4y^3/x^2y=9x^2y^2$$

rhondasommer · Answer

you basically subtract the exponents

rhondasommer · Answer

try that for $$3x^3y^2$$

anonymous · Answer

Would it just be 3x(y)?? No more exponents? Since when you subtracted 9x^4y^3, you ended up with 9x^2y^2.. I'm really sorry I'm not picking this up very well.

rhondasommer · Answer

its okay :)
$$3x^3y^2$$ -----$$x^2y$$
$$x^3/x^2~is~just~x^1$$

anonymous · Answer

Yes. I thought when you only had 1 exponent, they usually took the exponent off since it would just go back to being x anyways.

rhondasommer · Answer

$$y^5/y^3=y^2$$ and yes you are correct; i was just giving an example :)

rhondasommer · Answer

examples*

anonymous · Answer

Oh, well I'm glad I at least remembered something for this!

anonymous · Answer

I think I know how to do this now, so thank you for helping!

rhondasommer · Answer

yeah no problem :